Skip to main content

Energy

Type Alias Energy 

Source
pub type Energy = Qty<2, 1, -2, 0, 0, 0, 0>;
Expand description

Joules.

Aliased Type§

pub struct Energy(/* private fields */);

Implementations§

Source§

impl Energy

Source

pub fn j(v: f64) -> Energy

Joules.

Source

pub fn mj(v: f64) -> Energy

Millijoules.

Trait Implementations§

Source§

impl Div<Qty<0, 0, 0, 0, 1, 0, 0>> for Energy

Source§

type Output = Qty<2, 1, -2, 0, -1, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Temperature) -> HeatCapacity

Performs the / operation. Read more
Source§

impl Div<Qty<0, 0, 1, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<2, 1, -3, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Time) -> Power

Performs the / operation. Read more
Source§

impl Div<Qty<0, 1, 0, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<2, 0, -2, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Mass) -> LatentHeat

Performs the / operation. Read more
Source§

impl Div<Qty<1, 0, 0, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<1, 1, -2, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Length) -> Force

Performs the / operation. Read more
Source§

impl Div<Qty<1, 1, -2, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<1, 0, 0, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Force) -> Length

Performs the / operation. Read more
Source§

impl Div<Qty<2, 0, -2, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<0, 1, 0, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: LatentHeat) -> Mass

Performs the / operation. Read more
Source§

impl Div<Qty<2, 1, -2, 0, -1, 0, 0>> for Energy

Source§

type Output = Qty<0, 0, 0, 0, 1, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: HeatCapacity) -> Temperature

Performs the / operation. Read more
Source§

impl Div<Qty<2, 1, -3, 0, 0, 0, 0>> for Energy

Source§

type Output = Qty<0, 0, 1, 0, 0, 0, 0>

The resulting type after applying the / operator.
Source§

fn div(self, rhs: Power) -> Time

Performs the / operation. Read more