pub trait CeilingModPowerOf2Assign {
// Required method
fn ceiling_mod_power_of_2_assign(&mut self, other: u64);
}Expand description
Divides a number by $2^k$, replacing the number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
Required Methods§
fn ceiling_mod_power_of_2_assign(&mut self, other: u64)
Dyn Compatibility§
This trait is dyn compatible.
In older versions of Rust, dyn compatibility was called "object safety".
Implementations on Foreign Types§
Source§impl CeilingModPowerOf2Assign for i8
impl CeilingModPowerOf2Assign for i8
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.
Source§impl CeilingModPowerOf2Assign for i16
impl CeilingModPowerOf2Assign for i16
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.
Source§impl CeilingModPowerOf2Assign for i32
impl CeilingModPowerOf2Assign for i32
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.
Source§impl CeilingModPowerOf2Assign for i64
impl CeilingModPowerOf2Assign for i64
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.
Source§impl CeilingModPowerOf2Assign for i128
impl CeilingModPowerOf2Assign for i128
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.
Source§impl CeilingModPowerOf2Assign for isize
impl CeilingModPowerOf2Assign for isize
Source§fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
fn ceiling_mod_power_of_2_assign(&mut self, pow: u64)
Divides a number by $2^k$, replacing the first number by the remainder. The remainder is non-positive.
If the quotient were computed, the quotient and remainder would satisfy $x = q2^k + r$ and $0 \leq -r < 2^k$.
$$ x \gets x - 2^k\left \lceil\frac{x}{2^k} \right \rceil. $$
§Worst-case complexity
Constant time and additional memory.
§Panics
Panics if self is positive or Self::MIN, and pow is greater than or equal to
Self::WIDTH.
§Examples
See here.