pub struct PrisonValueMut<'a, T> { /* private fields */ }Expand description
Struct representing a mutable reference to a value that has been allowed to leave the Prison temporarily, but remains guarded by a wrapper to prevent it from leaking or never unlocking
PrisonValueMut
As long as the PrisonValueMut remains in scope, the element where it’s value resides in the Prison will remain marked as mutably referenced and unable to be referenced a second time. You can manually drop the PrisonValueMut out of scope by passing it as the first parameter to the function [PrisonValueMut::unguard(p_val_mut)]
You can obtain a PrisonValueMut by calling guard_mut() or guard_mut_idx() on a Prison
§Example
let prison: Prison<u32> = Prison::new();
let key_0 = prison.insert(10)?;
let mut grd_0 = prison.guard_mut(key_0)?;
assert_eq!(*grd_0, 10);
*grd_0 = 20;
PrisonValueMut::unguard(grd_0);
prison.visit_ref(key_0, |val_0| {
assert_eq!(*val_0, 20);
Ok(())
});Implementations§
Source§impl<'a, T> PrisonValueMut<'a, T>
impl<'a, T> PrisonValueMut<'a, T>
Sourcepub fn unguard(_prison_val_mut: Self)
pub fn unguard(_prison_val_mut: Self)
Manually end a PrisonValueMut value’s temporary guarded absence from the Prison
This method simply takes ownership of the PrisonValueMut and immediately lets it go out of scope,
causing it’s drop() method to be called and clearing its mutable reference in the Prison
§Example
let prison: Prison<u32> = Prison::new();
prison.insert(10)?;
let grd_0 = prison.guard_mut_idx(0)?;
// index 0 CANNOT be accessed here because it is being guarded outside the prison
assert!(prison.visit_ref_idx(0, |ref_0| Ok(())).is_err());
PrisonValueMut::unguard(grd_0);
// index 0 CAN be accessed here because it was returned to the prison
assert!(prison.visit_ref_idx(0, |ref_0| Ok(())).is_ok());