Struct dynasmrt::ExecutableBuffer
[−]
[src]
pub struct ExecutableBuffer { /* fields omitted */ }
A structure holding a buffer of executable memory
Methods
impl ExecutableBuffer
[src]
A structure wrapping some executable memory. It dereferences into a &[u8] slice.
fn ptr(&self, offset: AssemblyOffset) -> *const u8
Obtain a pointer into the executable memory from an offset into it.
When an offset returned from DynasmLabelApi::offset
is used, the resulting pointer
will point to the start of the first instruction after the offset call,
which can then be jumped or called to divert control flow into the executable
buffer. Note that if this buffer is accessed through an Executor, these pointers
will only be valid as long as its lock is held. When no locks are held,
The assembler is free to relocate the executable buffer when it requires
more memory than available.
Methods from Deref<Target=[u8]>
fn len(&self) -> usize
1.0.0
fn is_empty(&self) -> bool
1.0.0
fn first(&self) -> Option<&T>
1.0.0
Returns the first element of a slice, or None
if it is empty.
Examples
let v = [10, 40, 30]; assert_eq!(Some(&10), v.first()); let w: &[i32] = &[]; assert_eq!(None, w.first());Run
fn split_first(&self) -> Option<(&T, &[T])>
1.5.0
Returns the first and all the rest of the elements of a slice.
Examples
let x = &[0, 1, 2]; if let Some((first, elements)) = x.split_first() { assert_eq!(first, &0); assert_eq!(elements, &[1, 2]); }Run
fn split_last(&self) -> Option<(&T, &[T])>
1.5.0
Returns the last and all the rest of the elements of a slice.
Examples
let x = &[0, 1, 2]; if let Some((last, elements)) = x.split_last() { assert_eq!(last, &2); assert_eq!(elements, &[0, 1]); }Run
fn last(&self) -> Option<&T>
1.0.0
Returns the last element of a slice, or None
if it is empty.
Examples
let v = [10, 40, 30]; assert_eq!(Some(&30), v.last()); let w: &[i32] = &[]; assert_eq!(None, w.last());Run
fn get(&self, index: usize) -> Option<&T>
1.0.0
Returns the element of a slice at the given index, or None
if the
index is out of bounds.
Examples
let v = [10, 40, 30]; assert_eq!(Some(&40), v.get(1)); assert_eq!(None, v.get(3));Run
unsafe fn get_unchecked(&self, index: usize) -> &T
1.0.0
Returns a pointer to the element at the given index, without doing bounds checking. So use it very carefully!
Examples
let x = &[1, 2, 4]; unsafe { assert_eq!(x.get_unchecked(1), &2); }Run
fn as_ptr(&self) -> *const T
1.0.0
Returns an raw pointer to the slice's buffer
The caller must ensure that the slice outlives the pointer this function returns, or else it will end up pointing to garbage.
Modifying the slice may cause its buffer to be reallocated, which would also make any pointers to it invalid.
Examples
let x = &[1, 2, 4]; let x_ptr = x.as_ptr(); unsafe { for i in 0..x.len() { assert_eq!(x.get_unchecked(i), &*x_ptr.offset(i as isize)); } }Run
fn iter(&self) -> Iter<T>
1.0.0
Returns an iterator over the slice.
Examples
let x = &[1, 2, 4]; let mut iterator = x.iter(); assert_eq!(iterator.next(), Some(&1)); assert_eq!(iterator.next(), Some(&2)); assert_eq!(iterator.next(), Some(&4)); assert_eq!(iterator.next(), None);Run
fn windows(&self, size: usize) -> Windows<T>
1.0.0
Returns an iterator over all contiguous windows of length
size
. The windows overlap. If the slice is shorter than
size
, the iterator returns no values.
Panics
Panics if size
is 0.
Example
let slice = ['r', 'u', 's', 't']; let mut iter = slice.windows(2); assert_eq!(iter.next().unwrap(), &['r', 'u']); assert_eq!(iter.next().unwrap(), &['u', 's']); assert_eq!(iter.next().unwrap(), &['s', 't']); assert!(iter.next().is_none());Run
If the slice is shorter than size
:
let slice = ['f', 'o', 'o']; let mut iter = slice.windows(4); assert!(iter.next().is_none());Run
fn chunks(&self, size: usize) -> Chunks<T>
1.0.0
Returns an iterator over size
elements of the slice at a
time. The chunks are slices and do not overlap. If size
does not divide the
length of the slice, then the last chunk will not have length
size
.
Panics
Panics if size
is 0.
Example
let slice = ['l', 'o', 'r', 'e', 'm']; let mut iter = slice.chunks(2); assert_eq!(iter.next().unwrap(), &['l', 'o']); assert_eq!(iter.next().unwrap(), &['r', 'e']); assert_eq!(iter.next().unwrap(), &['m']); assert!(iter.next().is_none());Run
fn split_at(&self, mid: usize) -> (&[T], &[T])
1.0.0
Divides one slice into two at an index.
The first will contain all indices from [0, mid)
(excluding
the index mid
itself) and the second will contain all
indices from [mid, len)
(excluding the index len
itself).
Panics
Panics if mid > len
.
Examples
let v = [10, 40, 30, 20, 50]; let (v1, v2) = v.split_at(2); assert_eq!([10, 40], v1); assert_eq!([30, 20, 50], v2);Run
fn split<F>(&self, pred: F) -> Split<T, F> where F: FnMut(&T) -> bool
1.0.0
Returns an iterator over subslices separated by elements that match
pred
. The matched element is not contained in the subslices.
Examples
let slice = [10, 40, 33, 20]; let mut iter = slice.split(|num| num % 3 == 0); assert_eq!(iter.next().unwrap(), &[10, 40]); assert_eq!(iter.next().unwrap(), &[20]); assert!(iter.next().is_none());Run
If the first element is matched, an empty slice will be the first item returned by the iterator. Similarly, if the last element in the slice is matched, an empty slice will be the last item returned by the iterator:
let slice = [10, 40, 33]; let mut iter = slice.split(|num| num % 3 == 0); assert_eq!(iter.next().unwrap(), &[10, 40]); assert_eq!(iter.next().unwrap(), &[]); assert!(iter.next().is_none());Run
If two matched elements are directly adjacent, an empty slice will be present between them:
let slice = [10, 6, 33, 20]; let mut iter = slice.split(|num| num % 3 == 0); assert_eq!(iter.next().unwrap(), &[10]); assert_eq!(iter.next().unwrap(), &[]); assert_eq!(iter.next().unwrap(), &[20]); assert!(iter.next().is_none());Run
fn splitn<F>(&self, n: usize, pred: F) -> SplitN<T, F> where F: FnMut(&T) -> bool
1.0.0
Returns an iterator over subslices separated by elements that match
pred
, limited to returning at most n
items. The matched element is
not contained in the subslices.
The last element returned, if any, will contain the remainder of the slice.
Examples
Print the slice split once by numbers divisible by 3 (i.e. [10, 40]
,
[20, 60, 50]
):
let v = [10, 40, 30, 20, 60, 50]; for group in v.splitn(2, |num| *num % 3 == 0) { println!("{:?}", group); }Run
fn rsplitn<F>(&self, n: usize, pred: F) -> RSplitN<T, F> where F: FnMut(&T) -> bool
1.0.0
Returns an iterator over subslices separated by elements that match
pred
limited to returning at most n
items. This starts at the end of
the slice and works backwards. The matched element is not contained in
the subslices.
The last element returned, if any, will contain the remainder of the slice.
Examples
Print the slice split once, starting from the end, by numbers divisible
by 3 (i.e. [50]
, [10, 40, 30, 20]
):
let v = [10, 40, 30, 20, 60, 50]; for group in v.rsplitn(2, |num| *num % 3 == 0) { println!("{:?}", group); }Run
fn contains(&self, x: &T) -> bool where T: PartialEq<T>
1.0.0
Returns true if the slice contains an element with the given value.
Examples
let v = [10, 40, 30]; assert!(v.contains(&30)); assert!(!v.contains(&50));Run
fn starts_with(&self, needle: &[T]) -> bool where T: PartialEq<T>
1.0.0
Returns true if needle
is a prefix of the slice.
Examples
let v = [10, 40, 30]; assert!(v.starts_with(&[10])); assert!(v.starts_with(&[10, 40])); assert!(!v.starts_with(&[50])); assert!(!v.starts_with(&[10, 50]));Run
fn ends_with(&self, needle: &[T]) -> bool where T: PartialEq<T>
1.0.0
Returns true if needle
is a suffix of the slice.
Examples
let v = [10, 40, 30]; assert!(v.ends_with(&[30])); assert!(v.ends_with(&[40, 30])); assert!(!v.ends_with(&[50])); assert!(!v.ends_with(&[50, 30]));Run
fn binary_search(&self, x: &T) -> Result<usize, usize> where T: Ord
1.0.0
Binary search a sorted slice for a given element.
If the value is found then Ok
is returned, containing the
index of the matching element; if the value is not found then
Err
is returned, containing the index where a matching
element could be inserted while maintaining sorted order.
Example
Looks up a series of four elements. The first is found, with a
uniquely determined position; the second and third are not
found; the fourth could match any position in [1,4]
.
let s = [0, 1, 1, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]; assert_eq!(s.binary_search(&13), Ok(9)); assert_eq!(s.binary_search(&4), Err(7)); assert_eq!(s.binary_search(&100), Err(13)); let r = s.binary_search(&1); assert!(match r { Ok(1...4) => true, _ => false, });Run
fn binary_search_by<'a, F>(&'a self, f: F) -> Result<usize, usize> where F: FnMut(&'a T) -> Ordering
1.0.0
Binary search a sorted slice with a comparator function.
The comparator function should implement an order consistent
with the sort order of the underlying slice, returning an
order code that indicates whether its argument is Less
,
Equal
or Greater
the desired target.
If a matching value is found then returns Ok
, containing
the index for the matched element; if no match is found then
Err
is returned, containing the index where a matching
element could be inserted while maintaining sorted order.
Example
Looks up a series of four elements. The first is found, with a
uniquely determined position; the second and third are not
found; the fourth could match any position in [1,4]
.
let s = [0, 1, 1, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]; let seek = 13; assert_eq!(s.binary_search_by(|probe| probe.cmp(&seek)), Ok(9)); let seek = 4; assert_eq!(s.binary_search_by(|probe| probe.cmp(&seek)), Err(7)); let seek = 100; assert_eq!(s.binary_search_by(|probe| probe.cmp(&seek)), Err(13)); let seek = 1; let r = s.binary_search_by(|probe| probe.cmp(&seek)); assert!(match r { Ok(1...4) => true, _ => false, });Run
fn binary_search_by_key<'a, B, F>(&'a self, b: &B, f: F) -> Result<usize, usize> where B: Ord, F: FnMut(&'a T) -> B
1.10.0
Binary search a sorted slice with a key extraction function.
Assumes that the slice is sorted by the key, for instance with
sort_by_key
using the same key extraction function.
If a matching value is found then returns Ok
, containing the
index for the matched element; if no match is found then Err
is returned, containing the index where a matching element could
be inserted while maintaining sorted order.
Examples
Looks up a series of four elements in a slice of pairs sorted by
their second elements. The first is found, with a uniquely
determined position; the second and third are not found; the
fourth could match any position in [1,4]
.
let s = [(0, 0), (2, 1), (4, 1), (5, 1), (3, 1), (1, 2), (2, 3), (4, 5), (5, 8), (3, 13), (1, 21), (2, 34), (4, 55)]; assert_eq!(s.binary_search_by_key(&13, |&(a,b)| b), Ok(9)); assert_eq!(s.binary_search_by_key(&4, |&(a,b)| b), Err(7)); assert_eq!(s.binary_search_by_key(&100, |&(a,b)| b), Err(13)); let r = s.binary_search_by_key(&1, |&(a,b)| b); assert!(match r { Ok(1...4) => true, _ => false, });Run
fn to_vec(&self) -> Vec<T> where T: Clone
1.0.0
Copies self
into a new Vec
.
Examples
let s = [10, 40, 30]; let x = s.to_vec(); // Here, `s` and `x` can be modified independently.Run