Schnorr's proof of knowledge
Schnorr protocol to prove knowledge of 1 or more discrete logs in zero knowledge. Refer this for more details of Schnorr protocol.
Also implements the proof of knowledge of discrete log in pairing groups, i.e. given prover and verifier
both know (A1, Y1), and prover additionally knows B1, prove that e(A1, B1) = Y1. Similarly,
proving e(A2, B2) = Y2 when only prover knows A2 but both know (B2, Y2). See discrete_log_pairing.
Also implements the proof of inequality of discrete log (a value committed in a Pedersen commitment),
either with a public value or with another discrete log in Inequality. eg. Given a message m,
its commitment C = g * m + h * r and a public value v, proving that m ≠ v. Or given 2 messages
m1 and m2 and their commitments C1 = g * m1 + h * r1 and C2 = g * m2 + h * r2, proving m1 ≠ m2
Also implements the proof of inequality of discrete log when only one of the discrete log is known to
the prover. i.e. given y = g * x and z = h * k, prover and verifier know g, h, y and z and
prover additionally knows x but not k.
Also impelements partial Schnorr proof where response for some witnesses is not generated. This is useful when several Schnorr protocols are executed together and they share some witnesses. The response for those witnesses will be generated in one Schnorr proof while the other protocols will generate partial Schnorr proofs where responses for those witnesses will be missing.
We outline the steps of Schnorr protocol.
Prover wants to prove knowledge of x in y = g * x (y and g are public knowledge)
Step 1: Prover generates randomness r, and sends t = g * r to Verifier.
Step 2: Verifier generates random challenge c and send to Prover.
Step 3: Prover produces s = r + x*c, and sends s to Verifier.
Step 4: Verifier checks that g * s = (y * c) + t.
For proving knowledge of multiple messages like x_1 and x_2 in y = g_1*x_1 + g_2*x_2:
Step 1: Prover generates randomness r_1 and r_2, and sends t = g_1*r_1 + g_2*r_2 to Verifier
Step 2: Verifier generates random challenge c and send to Prover
Step 3: Prover produces s_1 = r_1 + x_1*c and s_2 = r_2 + x_2*c, and sends s_1 and s_2 to Verifier
Step 4: Verifier checks that g_1*s_1 + g_2*s_2 = y*c + t
Above can be generalized to more than 2 xs
There is another variant of Schnorr which gives shorter proof but is not implemented:
- Prover creates
rand thenT = r * G. - Prover computes challenge as
c = Hash(G||Y||T). - Prover creates response
s = r + c*xand sendscandsto the Verifier as proof. - Verifier creates
T'asT' = s * G - c * Yand computesc'asc' = Hash(G||Y||T') - Proof if valid if
c == c'
The problem with this variant is that it leads to poorer failure reporting as in case of failure, it can't be
pointed out which relation failed to verify. Eg. say there are 2 relations being proven which leads to 2
Ts T1 and T2 and 2 responses s1 and s2. If only the responses and challenge are sent then
in case of failure, the verifier will only know that its computed challenge c' doesn't match prover's given
challenge c but won't know which response s1 or s2 or both were incorrect. This is not the case
with the implemented variant as verifier checks 2 equations s1 = r1 + x1*c and s2 = r2 + x2*c