# Student T
$$
\psi(z) = \frac{\partial \log{\Gamma(z)}}{\partial z}
$$
$$
$$
|\mathbf{L}| = |\mathbf{L}^\top|
$$
## Univariate
$$
\begin{aligned}
\log{p(x \mid \mu, \sigma, \nu)} =& \log{\Gamma\left(\frac{\nu+1}{2}\right)} \\
&- \log{\Gamma \left(\frac{\nu}{2} \right)} - \frac{1}{2} \log{\nu} - \frac{1}{2} \log{\pi} - \log{\sigma} \\
& - \frac{\nu + 1}{2} \log{\left(1 + \frac{(x - \mu)^2} {\nu \sigma^2}\right)}
\end{aligned}
$$
### Diff x
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma, \nu)}}{\partial x}
&= - \frac{\nu + 1}{2} \left(1 + \frac{(x - \mu)^2}{\nu \sigma^2}\right)^{-1} \frac{2x - 2\mu}{\nu \sigma^2} \\
&= -(\nu + 1) \left(\frac{\nu \sigma^2 + (x - \mu)^2}{\nu \sigma^2}\right)^{-1} \frac{x - \mu}{\nu \sigma^2} \\
&= -\frac{(\nu + 1)(x - \mu)}{\nu \sigma^2 +(x - \mu)^2}
\end{aligned}
$$
### Diff mu
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma, \nu)}}{\partial \mu}
&= - \frac{\nu + 1}{2} \left(1 + \frac{(x - \mu)^2}{\nu \sigma^2}\right)^{-1} \left( -\frac{2x - 2\mu}{\nu \sigma^2} \right) \\
&= (\nu + 1) \left(\frac{\nu \sigma^2 + (x - \mu)^2}{\nu \sigma^2}\right)^{-1} \frac{x - \mu}{\nu \sigma^2} \\
&= \frac{(\nu + 1)(x - \mu)}{\nu \sigma^2 +(x - \mu)^2}
\end{aligned}
$$
### Diff sigma
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma, \nu)}}{\partial \sigma}
&= -\frac{1}{\sigma} - \frac{\nu + 1}{2} \left(1 + \frac{(x - \mu)^2}{\nu \sigma^2}\right)^{-1} \left( -\frac{2 (x - \mu)^2}{\nu \sigma^3} \right) \\
&= (\nu + 1) \left(\frac{\nu \sigma^2 + (x - \mu)^2}{\nu \sigma^2}\right)^{-1} \frac{(x - \mu)^2}{\nu \sigma^3} -\frac{1}{\sigma} \\
&= \frac{\nu + 1}{\sigma} \frac{(x - \mu)^2}{\nu \sigma^2 +(x - \mu)^2} -\frac{1}{\sigma}
\end{aligned}
$$
### Diff nu
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma, \nu)}}{\partial \nu}
=& \frac{1}{2} \psi \left(\frac{\nu + 1}{2} \right) - \frac{1}{2} \psi \left(\frac{\nu}{2}\right) - \frac{1}{2 \nu} \\
&+ \frac{\nu + 1}{2} \left(1 + \frac{(x - \mu)^2}{\nu \sigma^2}\right)^{-1} \frac{(x - \mu)^2}{\nu^2 \sigma^2} \\
&- \frac{1}{2} \log \left(1 + \frac{(x - \mu)^2}{\nu \sigma^2} \right)
\end{aligned}
$$
## Mutivariate
$$ \mathbf{L} \mathbf{L}^{ \top} = \bm{\Sigma} $$
$$ d = (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} (\mathbf{x} - \bm{\mu}) $$
$$
\begin{aligned}
\log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L}, \nu)} =& \log{\Gamma\left(\frac{\nu + n}{2}\right)} \\
&- \log{\Gamma \left(\frac{\nu}{2} \right)} - \frac{n}{2} \log{\nu} - \frac{n}{2} \log{\pi} - \log{|\mathbf{L}|} \\
& - \frac{\nu + n}{2} \log{\left(1 + \frac{1}{\nu}(\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} (\mathbf{x} - \bm{\mu})\right)}
\end{aligned}
$$
### Diff x
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L}, \nu)}}{\partial \mathbf{x}}
&= - \frac{\nu + n}{2} (1 + d)^{-1} \frac{2}{\nu}(\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} \\
&= - \frac{\nu + n}{\nu} (1 + d)^{-1} (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1}
\end{aligned}
$$
### Diff mu
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L}, \nu)}}{\partial \bm{\mu}}
&= - \frac{\nu + n}{2} (1 + d)^{-1} \left(-\frac{2}{\nu}(\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} \right) \\
&= \frac{\nu + n}{\nu} (1 + d)^{-1} (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1}
\end{aligned}
$$
### Diff lsigma
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L}, \nu)}}{\partial \mathbf{L}}
&= - \frac{\nu + n}{2} \left(1 + \frac{1}{\nu} d\right)^{-1} \left(-\frac{2}{\nu} (\mathbf{x} - \bm{\mu})^\top M (\mathbf{x} - \bm{\mu}) \right) \\
&= \frac{\nu + n}{\nu} (1 + \frac{1}{\nu} d)^{-1} (\mathbf{x} - \bm{\mu})^\top M (\mathbf{x} - \bm{\mu})
\end{aligned}
$$
$$
k_{ji}k_{ij} =
\begin{cases}
\frac{1}{l_{ij^2}} & \ \text{if} \ i = j \\
0 & \ \text{others}
\end{cases}
$$
$$
M = [l_{ab}^{-3}]_{ab}
$$
### Diff nu
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L}, \nu)}}{\partial \nu}
=& \frac{1}{2} \psi \left(\frac{\nu + n}{2} \right) - \frac{n}{2 \nu} - \frac{1}{2} \psi \left(\frac{\nu}{2}\right) \\
&+ \frac{\nu + n}{2} \left(1 + \frac{1}{\nu} d \right)^{-1} \left(-\frac{1}{\nu^2}d \right) \\
&- \frac{1}{2} \log \left(1 + \frac{1}{\nu} d \right) \\
=& \frac{1}{2} \left( \psi \left(\frac{\nu + n}{2} \right) - \frac{n}{\nu} - \psi \left(\frac{\nu}{2}\right) - \frac{(\nu + n) d}{\nu^2} \left(1 + \frac{1}{\nu} d \right)^{-1} - \log \left(1 + \frac{1}{\nu} d\right) \right)
\end{aligned}
$$