# Cauchye
$$
$$
|\mathbf{L}| = |\mathbf{L}^\top|
$$
## Univariate
$$
\begin{aligned}
\log{p(x \mid \mu, \sigma)} =& - \log{\pi} - \log{\sigma} \\
& - \log{\left(1 + \frac{(x - \mu)^2} {\sigma^2}\right)}
\end{aligned}
$$
### Diff x
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma)}}{\partial x}
&= - \left(1 + \frac{(x - \mu)^2}{\sigma^2}\right)^{-1} \frac{2x - 2\mu}{\sigma^2} \\
&= - \left(\frac{\sigma^2 + (x - \mu)^2}{\sigma^2}\right)^{-1} 2 \frac{x - \mu}{\sigma^2} \\
&= -\frac{2 (x - \mu)}{\sigma^2 +(x - \mu)^2}
\end{aligned}
$$
### Diff mu
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma)}}{\partial \mu}
&= - \left(1 + \frac{(x - \mu)^2}{\sigma^2}\right)^{-1} \left( - \frac{2x - 2\mu}{\sigma^2} \right) \\
&= \left(\frac{\sigma^2 + (x - \mu)^2}{\sigma^2}\right)^{-1} 2 \frac{x - \mu}{\sigma^2} \\
&= \frac{2 (x - \mu)}{\sigma^2 +(x - \mu)^2}
\end{aligned}
$$
### Diff sigma
$$
\begin{aligned}
\frac{\partial \log{p(x \mid \mu, \sigma)}}{\partial \sigma}
&= -\frac{1}{\sigma} - \left(1 + \frac{(x - \mu)^2}{\sigma^2}\right)^{-1} \left( -\frac{2 (x - \mu)^2}{\sigma^3} \right) \\
&= \left(\frac{\sigma^2 + (x - \mu)^2}{\sigma^2}\right)^{-1} \frac{2 (x - \mu)^2}{\sigma^3} -\frac{1}{\sigma} \\
&= \frac{2}{\sigma} \frac{(x - \mu)^2}{\sigma^2 +(x - \mu)^2} -\frac{1}{\sigma}
\end{aligned}
$$
## Mutivariate
$$ \mathbf{L} \mathbf{L}^{ \top} = \bm{\Sigma} $$
$$ d = (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} (\mathbf{x} - \bm{\mu}) $$
$$
\begin{aligned}
\log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L})} =& \log{\Gamma\left(\frac{1 + n}{2}\right)} \\
&- \log{\Gamma \left(\frac{1}{2} \right)} - \frac{n}{2} \log{\pi} - \log{|\mathbf{L}|} \\
& - \frac{1 + n}{2} \log{\left(1 + (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} (\mathbf{x} - \bm{\mu})\right)}
\end{aligned}
$$
### Diff x
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L})}}{\partial \mathbf{x}}
&= - \frac{1 + n}{2} (1 + d)^{-1} 2(\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} \\
&= - (1 + n) (1 + d)^{-1} (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1}
\end{aligned}
$$
### Diff mu
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L})}}{\partial \bm{\mu}}
&= - \frac{1 + n}{2} (1 + d)^{-1} \left(-2(\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1} \right) \\
&= (1 + n) (1 + d)^{-1} (\mathbf{x} - \bm{\mu})^\top \bm{\Sigma}^{-1}
\end{aligned}
$$
### Diff lsigma
$$
\begin{aligned}
\frac{\partial \log{p(\mathbf{x} \mid \bm{\mu}, \mathbf{L})}}{\partial \mathbf{L}}
&= - \frac{1 + n}{2} \left(1 + d\right)^{-1} \left(-2 (\mathbf{x} - \bm{\mu})^\top M (\mathbf{x} - \bm{\mu}) \right) \\
&= (1 + n) (1 + d)^{-1} (\mathbf{x} - \bm{\mu})^\top M (\mathbf{x} - \bm{\mu})
\end{aligned}
$$
$$
k_{ji}k_{ij} =
\begin{cases}
\frac{1}{l_{ij^2}} & \ \text{if} \ i = j \\
0 & \ \text{others}
\end{cases}
$$
$$
M = [l_{ab}^{-3}]_{ab}
$$