iter-tree
This library provide an easy way to transform iterators into trees. This can be useful when building simple parsers to convert a stream of token into a tree of token.
It provide two types of tree:
-
The default one,
Tree
is based onVec
from the standard library. -
The second one is based on
VecDeque
from the standard libray. To get this one, you have to activate thedeque
feature flag.
The goals for the future of this crate includes but are not limited to :
- Providing other types of Trees, notably some that separate the item that inited and terminated a branch.
- Adding more methods to build Trees such as for example a
tree_map
andtree_deque_map
method that would map the item before including it in the Tree.
Usage
The creation of a tree is controlled with the BranchControl
enum.
This enum has three variants :
- BranchControl::Start
- Is used to start nesting the items of the iterator into a new branch.
- BranchControl::Continue
- Is used to keep the item in the same branch as the previous ones
- BranchControl::End
- Is used to get back up to the previous branch to put the next items.
Note:
When filling a branch started with
BranchControl::Start
, no crash or error will happens if the iterator ends before encountering the correspondingBranchControl::End
. Similarly, any unmatchedBranchControl::End
will simply be ignored.If you want to check for these kind of situations, you can use a trick such as the depth counter showed in the below example.
Example
use *;
let mut depth = 0;
let tree = "a+(b+c)+d"
.chars
.into_iter
.tree
.;
println!;
assert_eq!;
[
)
)
[
)
)
)
)
)
)
)
)
)
To go further
Additionally you can create a struct that implements the Controller
trait to replace the closure from the previous example.
Here is an example of how this can be applied :
use *;
let mut controller = default;
let _1 = "< ( < > ) >"
.chars
.tree
.;
assert!;
let mut controller = default;
let _b = "<(>)".chars.tree.;
assert!