finitely -- Optimized Finite Field Arithmetic
This crate implements arithmetic on rings of the form (Z/nZ)[x]/(p(x)) with arbitrary n and p. It aims to be performant and feature-rich.
Example usage:
use make_ring;
make_ring!
let x = from_coeffs;
assert_eq!;
// Notice that 3 * 2 = 6, which is 1 modulo 5.
// Therefore x * (3 * x) = x * x * 3 = 2 * 3 = 1.
// Therefore the inverse of x is 3x.
assert_eq!;
let x_plus_one = x + 1;
assert_eq!;
assert_eq!;
What does this implement (but for non-mathematicians)?
This crate lets you represent polynomials that look like a[0] + a[1]x + a[2]x^2 + ... + a[k]x^k, with equivalences enforced to make it constant-size. Namely, each one of the coefficients a[i] is taken modulo n (the equivalence here is to say that n is equivalent to zero), and that the polynomial p is equivalent to zero.
What does the second equivalence mean? Consider a polynomial that is of this shape: p(x) = x^m + b[m-1]x^(m-1) + ... + b[2]x^2 + b[1]x + b[0] (it is important that the coefficient of x^m be one). If we declare that p(x) is equivalent to zero, then we have essentially said that:
x^m = -(b[m-1]x^(m-1) + ... + b[2]x^2 + b[1]x + b[0])
So every polynomial with degree (highest power of x) which is greater than or equal to m can be rewritten as a polynomial of smaller degree.
Why do mathematicians care?
If we pick n carefully (prime), and p carefully (irreducible), then the mathematical structure we get out is what is known as a field. A field is a mathematical structure where you have the four typical operations you are used to from f32: +, -, *, and /. If n and p are not chosen carefully, then / does not exist (but the other three still do).
How is this useful to a non-mathematician?
This crate can be used to represent constant-length vectors of integers modulo n. If you do not use * or / (by another polynomial, and instead just regular integers), then you have an array of length m (where m is the degree of p) of integers modulo n.