Function flatten

pub const fn flatten<T, const N: usize>(vals: &[[T; N]]) -> &[T]

Takes a &[[T; N]], and flattens it to a &[T].

Panics

This panics if the length of the resulting slice would overflow a usize.

This is only possible when flattening a slice of arrays of zero-sized types, and thus tends to be irrelevant in practice. If size_of::<T>() > 0, this will never panic.

Examples

assert_eq!(array_util::flatten(&[[1, 2, 3], [4, 5, 6]]), &[1, 2, 3, 4, 5, 6]);

assert_eq!(
    array_util::flatten(&[[1, 2, 3], [4, 5, 6]]),
    array_util::flatten(&[[1, 2], [3, 4], [5, 6]]),
);

let slice_of_empty_arrays: &[[i32; 0]] = &[[], [], [], [], []];
assert!(array_util::flatten(&slice_of_empty_arrays).is_empty());

let empty_slice_of_arrays: &[[u32; 10]] = &[];
assert!(array_util::flatten(&empty_slice_of_arrays).is_empty());