algos/numerics/factorial.rs
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//! Factorial module.
//!
//! Since calculate fatorial is simple enought, we will only implement the iterator that
//! keeps giving a ever increasing number.
//!
//! _Only implement for big numbers cause the number grows big super fast._
use num::{BigUint, One};
/// Factorial iterator using big numbers.
///
/// # Example
/// Print the 100 first factorial numbers.
///
/// ```rust
/// # use algos::numerics::BigFactorial;
/// # fn main() {
/// BigFactorial::new().enumerate().take(100).for_each(|(i, v)| println!("{}!: {}", i, v));
/// # }
/// ```
#[derive(Debug, Clone)]
pub struct BigFactorial {
/// Index we are in.
index: u128,
/// Last value calculated.
///
/// We can do it without this value, but using it, we increase memory consuption, but
/// the iterator became faster.
last: BigUint,
}
impl BigFactorial {
/// Creates a new iterator starting at the first number of the sequence.
pub fn new() -> Self { BigFactorial { last: BigUint::one(), index: 0 } }
/// Create a new iterator with the first factorial number beeing the `nth` factorial
/// number.
pub fn at(nth: impl Into<u128>) -> Self {
let index = nth.into();
BigFactorial { index, last: (1..index).map(BigUint::from).product() }
}
}
impl Iterator for BigFactorial {
type Item = BigUint;
fn next(&mut self) -> Option<Self::Item> {
if self.index == 0 {
self.index += 1;
Some(BigUint::one())
} else {
self.last *= self.index;
self.index += 1;
Some(self.last.clone())
}
}
}
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn iterator_bignum_test() {
let sure: Vec<_> = vec![1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362_880, 3_628_800]
.iter()
.map(|x| BigUint::from(*x as u64))
.collect();
let test: Vec<_> = BigFactorial::new().take(sure.len()).collect();
assert_eq!(sure, test);
}
#[test]
fn iterator_bignum_at_test() {
let sure: Vec<_> = vec![120, 720, 5040, 40320, 362_880, 3_628_800]
.iter()
.map(|x| BigUint::from(*x as u64))
.collect();
let test: Vec<_> = BigFactorial::at(5u32).take(sure.len()).collect();
assert_eq!(sure, test);
}
}