Function is_python_reserved_word
Source pub fn is_python_reserved_word(input: &str) -> bool
Expand description
Returns whether input is either a hard or soft Python reserved word.
examples/basic_usage.rs (
line 9)
3fn main() -> Result<(), use_python_keyword::PythonKeywordParseError> {
4 let keyword: PythonKeyword = "async".parse()?;
5 let soft_keyword: PythonSoftKeyword = "match".parse()?;
6
7 assert_eq!(keyword.to_string(), "async");
8 assert_eq!(soft_keyword.as_str(), "match");
9 assert!(is_python_reserved_word("case"));
10 Ok(())
11}