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use super::Q96;
use alloy_primitives::U256;
use uniswap_v3_math::error::UniswapV3MathError;
const ONE: U256 = U256::from_limbs([1, 0, 0, 0]);
const TWO: U256 = U256::from_limbs([2, 0, 0, 0]);
const THREE: U256 = U256::from_limbs([3, 0, 0, 0]);
/// Calculates floor(a×b÷denominator) with full precision. Throws if result overflows a uint256 or denominator == 0
///
/// # Arguments
///
/// * `a`: The multiplicand
/// * `b`: The multiplier
/// * `denominator`: The divisor
///
/// returns: Result<U256, UniswapV3MathError>
///
pub fn mul_div(a: U256, b: U256, mut denominator: U256) -> Result<U256, UniswapV3MathError> {
// 512-bit multiply [prod1 prod0] = a * b
// Compute the product mod 2**256 and mod 2**256 - 1
// then use the Chinese Remainder Theorem to reconstruct
// the 512 bit result. The result is stored in two 256
// variables such that product = prod1 * 2**256 + prod0
let mm = a.mul_mod(b, U256::MAX);
// Least significant 256 bits of the product
let mut prod_0 = a * b;
let mut prod_1 = mm - prod_0 - U256::from_limbs([(mm < prod_0) as u64, 0, 0, 0]);
// Make sure the result is less than 2**256.
// Also prevents denominator == 0
if denominator <= prod_1 {
if denominator.is_zero() {
return Err(UniswapV3MathError::DenominatorIsZero);
}
return Err(UniswapV3MathError::DenominatorIsLteProdOne);
}
// Handle non-overflow cases, 256 by 256 division
if prod_1.is_zero() {
return Ok(prod_0 / denominator);
}
///////////////////////////////////////////////
// 512 by 256 division.
///////////////////////////////////////////////
// Make division exact by subtracting the remainder from [prod1 prod0]
// Compute remainder using mul_mod
let remainder = a.mul_mod(b, denominator);
// Subtract 256 bit number from 512 bit number
prod_1 -= U256::from_limbs([(remainder > prod_0) as u64, 0, 0, 0]);
prod_0 -= remainder;
// Factor powers of two out of denominator
// Compute largest power of two divisor of denominator.
// Always >= 1.
let mut twos = (U256::ZERO - denominator) & denominator;
// Divide denominator by power of two
denominator /= twos;
// Divide [prod1 prod0] by the factors of two
prod_0 /= twos;
// Shift in bits from prod1 into prod0. For this we need
// to flip `twos` such that it is 2**256 / twos.
// If twos is zero, then it becomes one
twos = (U256::ZERO - twos) / twos + ONE;
prod_0 |= prod_1 * twos;
// Invert denominator mod 2**256
// Now that denominator is an odd number, it has an inverse
// modulo 2**256 such that denominator * inv = 1 mod 2**256.
// Compute the inverse by starting with a seed that is correct
// correct for four bits. That is, denominator * inv = 1 mod 2**4
let mut inv = (THREE * denominator) ^ TWO;
// Now use Newton-Raphson iteration to improve the precision.
// Thanks to Hensel's lifting lemma, this also works in modular
// arithmetic, doubling the correct bits in each step.
inv *= TWO - denominator * inv; // inverse mod 2**8
inv *= TWO - denominator * inv; // inverse mod 2**16
inv *= TWO - denominator * inv; // inverse mod 2**32
inv *= TWO - denominator * inv; // inverse mod 2**64
inv *= TWO - denominator * inv; // inverse mod 2**128
inv *= TWO - denominator * inv; // inverse mod 2**256
// Because the division is now exact we can divide by multiplying
// with the modular inverse of denominator. This will give us the
// correct result modulo 2**256. Since the preconditions guarantee
// that the outcome is less than 2**256, this is the final result.
// We don't need to compute the high bits of the result and prod1
// is no longer required.
Ok(prod_0 * inv)
}
/// Calculates ceil(a×b÷denominator) with full precision. Throws if result overflows a uint256 or denominator == 0
///
/// # Arguments
///
/// * `a`: The multiplicand
/// * `b`: The multiplier
/// * `denominator`: The divisor
///
/// returns: Result<U256, UniswapV3MathError>
///
pub fn mul_div_rounding_up(
a: U256,
b: U256,
denominator: U256,
) -> Result<U256, UniswapV3MathError> {
let result = mul_div(a, b, denominator)?;
if a.mul_mod(b, denominator).is_zero() {
Ok(result)
} else if result == U256::MAX {
Err(UniswapV3MathError::ResultIsU256MAX)
} else {
Ok(result + ONE)
}
}
/// Calculates a * b / 2^96 with full precision.
pub fn mul_div_96(a: U256, b: U256) -> Result<U256, UniswapV3MathError> {
let prod0 = a * b;
let mm = a.mul_mod(b, U256::MAX);
let prod1 = mm - prod0 - U256::from_limbs([(mm < prod0) as u64, 0, 0, 0]);
if prod1.ge(&Q96) {
return Err(UniswapV3MathError::DenominatorIsLteProdOne);
}
Ok((prod0 >> 96) | (prod1 << 160))
}