Function get_file_name_without_extension

pub fn get_file_name_without_extension(path: &str) -> Option<String>

Extract the file name without its extension

This function extracts just the file name portion of a path, excluding both the directory path and the file extension.

Arguments

• path - The file path to extract the name from

Returns

Some(String) containing the file name without extension if present, None otherwise.

Examples

use tree_parser::get_file_name_without_extension;
 
assert_eq!(get_file_name_without_extension("test.py"), Some("test".to_string()));
assert_eq!(get_file_name_without_extension("path/to/file.rs"), Some("file".to_string()));
assert_eq!(get_file_name_without_extension("no_extension"), Some("no_extension".to_string()));