Macro stack_buf::stack_vec [−][src]
Creates a StackVec
containing the arguments.
stack_vec!
allows StackVec
s to be defined with the same syntax as array expressions.
There are two forms of this macro:
- Creates a empty
StackVec
:
use stack_buf::{StackVec, stack_vec}; let vec: StackVec<i32, 8> = stack_vec![]; assert!(vec.is_empty()); assert_eq!(vec.capacity(), 8); let vec = stack_vec![i32; 16]; assert!(vec.is_empty()); assert_eq!(vec.capacity(), 16);
- Creates a
StackVec
containing a given list of elements:
use stack_buf::{StackVec, stack_vec}; let vec = stack_vec![128#1, 2, 3]; assert_eq!(vec.capacity(), 128); assert_eq!(vec[0], 1); assert_eq!(vec[1], 2); assert_eq!(vec[2], 3); let vec = stack_vec![1, 2, 3]; assert_eq!(vec.capacity(), 3);
- Creates a
StackVec
from a given element and size:
use stack_buf::{StackVec, stack_vec}; let v = stack_vec![0x8000#1; 3]; assert_eq!(v.as_slice(), [1, 1, 1]); assert_eq!(v.capacity(), 0x8000); let v = stack_vec![1; 3]; assert_eq!(v.capacity(), 3);
Note that unlike array expressions this syntax supports all elements
which implement Clone
and the number of elements doesn’t have to be
a constant.
This will use clone
to duplicate an expression, so one should be careful
using this with types having a nonstandard Clone
implementation. For
example, stack_vec![Rc::new(1); 5]
will create a vector of five references
to the same boxed integer value, not five references pointing to independently
boxed integers.