pub fn parse_block_expr(pair: Pair<'_, Rule>) -> Result<Expr>Expand description
Parse block expression
The PEG grammar uses (block_statement ~ ";"?)* ~ block_item? where ";"?
is silent/optional. To implement semicolon-suppresses-return semantics
({ 1; } yields () while { 1 } yields 1), we inspect the raw source
text after each block_statement span to detect whether a semicolon was
actually present.