Skip to main content

pounce_sensitivity/
backsolver.rs

1//! `SensBacksolver` trait — abstract backsolver against a converged KKT factor.
2//!
3//! Mirrors upstream
4//! [`SensBacksolver.hpp`](../../../ref/Ipopt/contrib/sIPOPT/src/SensBacksolver.hpp).
5//!
6//! # What this is
7//!
8//! After pounce's IPM converges, the KKT factor `K` is stored on the
9//! algorithm side (`pounce-algorithm::kkt::PdFullSpaceSolver`).
10//! sIPOPT runs a small number of backsolves against that factor to
11//! build the sensitivity matrix `P = K⁻¹ A` (see
12//! [`crate::p_calculator::PCalculator`]). The trait surface is just
13//! "solve `K · lhs = rhs`"; concrete impls plug in either the real
14//! `AugSystemSolver` (Phase B.2) or a synthetic dense-LU backsolver
15//! (Phase B.1, this file, for unit testing the sensitivity math).
16//!
17//! Upstream `SensSimpleBacksolver` is the analogous wrapper around
18//! Ipopt's `AugSystemSolver`
19//! ([`SensSimpleBacksolver.{hpp,cpp}`](../../../ref/Ipopt/contrib/sIPOPT/src/SensSimpleBacksolver.hpp)).
20
21use pounce_common::types::Number;
22
23/// Solve `K · lhs = rhs` against the converged KKT factor. Returns
24/// `false` on failure (e.g. backend reports `Singular`).
25///
26/// Mirrors `Ipopt::SensBacksolver::Solve`
27/// ([`SensBacksolver.hpp:28-31`](../../../ref/Ipopt/contrib/sIPOPT/src/SensBacksolver.hpp)).
28/// Pounce takes flat `&[Number]` / `&mut [Number]` rather than
29/// upstream's block-structured `IteratesVector` because the
30/// sensitivity-side data is naturally flat; if the algorithm-side
31/// wrapper in Phase B.2 needs the block layout it converts before
32/// calling.
33pub trait SensBacksolver {
34    /// Size of the linear system in entries (length of `lhs` and
35    /// `rhs`). The backsolver's notion of "full state" — pounce's
36    /// IPM uses the compound `(x, s, λ_c, λ_d, z_l, z_u, v_l, v_u)`
37    /// concatenation here.
38    fn dim(&self) -> usize;
39
40    /// Solve `K · lhs = rhs`. The implementation may use `rhs` as
41    /// scratch; callers should treat it as moved-from on return.
42    /// `lhs` must have length `self.dim()`.
43    fn solve(&self, rhs: &[Number], lhs: &mut [Number]) -> bool;
44}
45
46/// Synthetic dense-LU backsolver. Used in this crate's tests to
47/// validate the sensitivity math against known-good linear-algebra
48/// answers without standing up the full pounce IPM. Phase B.2 ships
49/// a real `pounce-algorithm`-backed implementation; this stays for
50/// regression tests and as a reference for the trait contract.
51///
52/// Stores a row-major `n × n` matrix and reuses an in-place
53/// Gaussian-elimination LU factor with partial pivoting. Numerical
54/// stability is fine for the small problem sizes the unit tests
55/// exercise (n ≤ 16).
56#[derive(Debug, Clone)]
57pub struct DenseLuBacksolver {
58    n: usize,
59    /// Factored `K` in row-major order: contains `L` (unit lower)
60    /// and `U` (upper) packed in-place per Doolittle.
61    lu: Vec<Number>,
62    /// Row-permutation order: row `piv[i]` of the original `K`
63    /// ended up in row `i` of the factor.
64    piv: Vec<usize>,
65}
66
67impl DenseLuBacksolver {
68    /// Build from a row-major `n × n` matrix. Returns `Err(())` if
69    /// the matrix is exactly singular at LU time (zero pivot after
70    /// pivoting).
71    pub fn from_dense(n: usize, a_row_major: &[Number]) -> Result<Self, ()> {
72        if a_row_major.len() != n * n {
73            return Err(());
74        }
75        let mut lu = a_row_major.to_vec();
76        let mut piv: Vec<usize> = (0..n).collect();
77        for k in 0..n {
78            // Partial pivot: find row with largest |lu[r,k]| for r >= k.
79            let mut best = k;
80            let mut best_mag = lu[k * n + k].abs();
81            for r in (k + 1)..n {
82                let mag = lu[r * n + k].abs();
83                if mag > best_mag {
84                    best = r;
85                    best_mag = mag;
86                }
87            }
88            if best_mag == 0.0 {
89                return Err(());
90            }
91            if best != k {
92                piv.swap(k, best);
93                for j in 0..n {
94                    let tmp = lu[k * n + j];
95                    lu[k * n + j] = lu[best * n + j];
96                    lu[best * n + j] = tmp;
97                }
98            }
99            // Eliminate below pivot.
100            let inv_p = 1.0 / lu[k * n + k];
101            for r in (k + 1)..n {
102                let m = lu[r * n + k] * inv_p;
103                lu[r * n + k] = m;
104                for j in (k + 1)..n {
105                    let upd = lu[k * n + j];
106                    lu[r * n + j] -= m * upd;
107                }
108            }
109        }
110        Ok(Self { n, lu, piv })
111    }
112}
113
114impl SensBacksolver for DenseLuBacksolver {
115    fn dim(&self) -> usize {
116        self.n
117    }
118
119    fn solve(&self, rhs: &[Number], lhs: &mut [Number]) -> bool {
120        if rhs.len() != self.n || lhs.len() != self.n {
121            return false;
122        }
123        // Apply row permutation first.
124        for i in 0..self.n {
125            lhs[i] = rhs[self.piv[i]];
126        }
127        // Forward solve: L · y = P · rhs (L unit lower in `lu`).
128        for i in 0..self.n {
129            let mut s = lhs[i];
130            for j in 0..i {
131                s -= self.lu[i * self.n + j] * lhs[j];
132            }
133            lhs[i] = s;
134        }
135        // Back solve: U · x = y.
136        for i in (0..self.n).rev() {
137            let mut s = lhs[i];
138            for j in (i + 1)..self.n {
139                s -= self.lu[i * self.n + j] * lhs[j];
140            }
141            let p = self.lu[i * self.n + i];
142            if p == 0.0 {
143                return false;
144            }
145            lhs[i] = s / p;
146        }
147        true
148    }
149}
150
151#[cfg(test)]
152mod tests {
153    use super::*;
154
155    /// Solve the small symmetric system `A x = b`:
156    ///   2 -1  0 | 1
157    ///  -1  2 -1 | 0
158    ///   0 -1  2 | 0
159    /// Closed-form: x = (3/4, 1/2, 1/4).
160    #[test]
161    fn dense_lu_solves_3x3_symmetric() {
162        #[rustfmt::skip]
163        let a = vec![
164             2.0, -1.0,  0.0,
165            -1.0,  2.0, -1.0,
166             0.0, -1.0,  2.0,
167        ];
168        let solver = DenseLuBacksolver::from_dense(3, &a).expect("factor");
169        let b = [1.0, 0.0, 0.0];
170        let mut x = [0.0; 3];
171        assert!(solver.solve(&b, &mut x));
172        assert!((x[0] - 0.75).abs() < 1e-12, "x[0] = {}", x[0]);
173        assert!((x[1] - 0.50).abs() < 1e-12, "x[1] = {}", x[1]);
174        assert!((x[2] - 0.25).abs() < 1e-12, "x[2] = {}", x[2]);
175    }
176
177    /// Pivoting check: a matrix whose first pivot is zero (must swap
178    /// rows). Direct closed-form: A x = b for
179    ///   0  1  | 2     →  x = (2, 1) after swap
180    ///   1  0  | 1
181    #[test]
182    fn dense_lu_handles_zero_first_pivot() {
183        let a = vec![0.0, 1.0, 1.0, 0.0];
184        let solver = DenseLuBacksolver::from_dense(2, &a).expect("factor");
185        let b = [2.0, 1.0];
186        let mut x = [0.0; 2];
187        assert!(solver.solve(&b, &mut x));
188        assert!((x[0] - 1.0).abs() < 1e-12, "x[0] = {}", x[0]);
189        assert!((x[1] - 2.0).abs() < 1e-12, "x[1] = {}", x[1]);
190    }
191
192    #[test]
193    fn dense_lu_rejects_singular_matrix() {
194        // Rank-deficient: rows are linearly dependent.
195        let a = vec![1.0, 2.0, 2.0, 4.0];
196        assert!(DenseLuBacksolver::from_dense(2, &a).is_err());
197    }
198
199    #[test]
200    fn solve_rejects_wrong_dim() {
201        let a = vec![1.0, 0.0, 0.0, 1.0];
202        let s = DenseLuBacksolver::from_dense(2, &a).expect("ok");
203        let b = [1.0];
204        let mut x = [0.0; 2];
205        assert!(!s.solve(&b, &mut x));
206    }
207}