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primitive_float_cot

Function primitive_float_cot 

Source
pub fn primitive_float_cot<T>(x: T) -> T
where Float: From<T> + PartialOrd<T>, for<'a> T: ExactFrom<&'a Float> + RoundingFrom<&'a Float> + PrimitiveFloat,
Expand description

Computes $\cot x$, the cotangent of a primitive float, correctly rounded. Neither the standard library nor libm provides a cotangent.

$$ f(x) = \cot x+\varepsilon. $$

  • If $x$ is not finite, $\varepsilon$ may be ignored or assumed to be 0.
  • If $x$ is finite, then $|\varepsilon| < 2^{\lfloor\log_2 |\cot x|\rfloor-p}$, where $p$ is the precision of the output (24 if T is a f32 and 53 if T is a f64).

Special cases:

  • $f(\text{NaN})=\text{NaN}$
  • $f(\pm\infty)=\text{NaN}$
  • $f(\pm0.0)=\pm\infty$

Overflow is possible: the cotangent of a tiny $x$ is close to $1/x$, so an $x$ with $|x|$ below about $2^{-128}$ has a cotangent beyond the largest f32, and one below about $2^{-1024}$ beyond the largest f64; the result is then $\pm\infty$. No f32 or f64 is close enough to a nonzero multiple of $\pi$ for its cotangent to overflow that way, nor close enough to an odd multiple of $\pi/2$ for it to underflow: the floats are spaced far more widely there than either would take.

§Worst-case complexity

Constant time and additional memory.

§Examples

use malachite_base::num::basic::traits::NegativeInfinity;
use malachite_base::num::float::NiceFloat;
use malachite_float::float::arithmetic::cot::primitive_float_cot;

assert!(primitive_float_cot(f32::NAN).is_nan());
assert!(primitive_float_cot(f32::INFINITY).is_nan());
assert!(primitive_float_cot(f32::NEGATIVE_INFINITY).is_nan());
assert_eq!(
    NiceFloat(primitive_float_cot(0.0f32)),
    NiceFloat(f32::INFINITY)
);
assert_eq!(
    NiceFloat(primitive_float_cot(-0.0f32)),
    NiceFloat(f32::NEGATIVE_INFINITY)
);
assert_eq!(
    NiceFloat(primitive_float_cot(1.0f32)),
    NiceFloat(0.64209265)
);
assert_eq!(
    NiceFloat(primitive_float_cot(1.0f64)),
    NiceFloat(0.6420926159343308)
);