pub trait RootAssignRem<POW> {
    type RemOutput;

    // Required method
    fn root_assign_rem(&mut self, exp: POW) -> Self::RemOutput;
}
Expand description

Replaces a number with the floor of its $n$th root, returning the remainder.

Required Associated Types§

Required Methods§

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fn root_assign_rem(&mut self, exp: POW) -> Self::RemOutput

Implementations on Foreign Types§

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impl RootAssignRem<u64> for u8

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fn root_assign_rem(&mut self, exp: u64) -> u8

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = u8

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impl RootAssignRem<u64> for u16

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fn root_assign_rem(&mut self, exp: u64) -> u16

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = u16

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impl RootAssignRem<u64> for u32

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fn root_assign_rem(&mut self, exp: u64) -> u32

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = u32

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impl RootAssignRem<u64> for u64

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fn root_assign_rem(&mut self, exp: u64) -> u64

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = u64

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impl RootAssignRem<u64> for u128

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fn root_assign_rem(&mut self, exp: u64) -> u128

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = u128

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impl RootAssignRem<u64> for usize

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fn root_assign_rem(&mut self, exp: u64) -> usize

Replaces an integer with the floor of its $n$th root, and returns the remainder (the difference between the original integer and the $n$th power of the floor).

$f(x, n) = x - \lfloor\sqrt[n]{x}\rfloor^n$,

$x \gets \lfloor\sqrt[n]{x}\rfloor$.

§Worst-case complexity

Constant time and additional memory.

§Panics

Panics if exp is zero.

§Examples

See here.

§

type RemOutput = usize

Implementors§