Function div_mod
Source pub fn div_mod(a: BigUint, b: BigUint, p: &BigUint) -> BigUint
Expand description
Divides two BigUint
numbers modulo a third BigUint
number.
§Arguments
a
- The numerator as a BigUint
.
b
- The denominator as a BigUint
.
p
- The modulus as a BigUint
.
§Returns
The result of the division modulo p
as a BigUint
.