Function div_mod
Source pub fn div_mod(a: BigUint, b: BigUint, p: &BigUint) -> BigUint
Expand description
Divides two BigUint numbers modulo a third BigUint number.
§Arguments
a - The numerator as a BigUint.
b - The denominator as a BigUint.
p - The modulus as a BigUint.
§Returns
The result of the division modulo p as a BigUint.