pub fn zip_eq<I, J>(
i: I,
j: J,
) -> ZipEq<<I as IntoIterator>::IntoIter, <J as IntoIterator>::IntoIter>where
I: IntoIterator,
J: IntoIterator,Expand description
Iterate i and j in lock step.
Panics if the iterators are not of the same length.
IntoIterator enabled version of Itertools::zip_eq.
use itertools::zip_eq;
let data = [1, 2, 3, 4, 5];
for (a, b) in zip_eq(&data[..data.len() - 1], &data[1..]) {
/* loop body */
}