pub fn union<T, L, R>(a: L, b: R) -> impl Iterator<Item = T>Expand description
Take the union of two sets represented by sorted, deduplicated iterators.
If an element is in both iterators, then only the one from a is yielded.
This behaviour can be overridden by using union_by().
Time complexity: O(a.len() + b.len()).
ยงExamples
use iter_set::union;
let a = [1, 2];
let b = [2, 3];
assert!(union(&a, &b).eq(&[1, 2, 3]));