pub fn intersection<T, L, R>(a: L, b: R) -> impl Iterator<Item = T>Expand description
Take the intersection of two sets represented by sorted, deduplicated iterators.
The elements returned will all be from a. This behaviour can be overridden by
using intersection_by().
Time complexity: O(a.len() + b.len()).
ยงExamples
use iter_set::intersection;
let a = [1, 2];
let b = [2, 3];
assert!(intersection(&a, &b).eq(&[2]));