Crate hipool

Source
Expand description

提供内存池管理机制, 支持从堆上动态分配,或者事先分配的一块内存空间,可能在堆上也可能在栈上.

§Examples

简单类型,直接传递初始值,会有一次拷贝

use hipool::{ MemPool, Boxed};
let pool = MemPool::new(0);
let psize = Boxed::new_in(&pool, 100).unwrap();
assert_eq!(*psize, 100);

复杂类型,构造过程中还会涉及动态申请内存.

use core::ptr;
use hipool::{ MemPool, Boxed};

let pool = MemPool::new(0);
struct Foo<'a> {
    val: Boxed<'a, i32, MemPool>,
}
let foo = Boxed::new_then_in(&pool, || {
    Ok(Foo {
        val: Boxed::new_in(&pool, 100)?,
    })
}).unwrap();
assert_eq!(*foo.val, 100);

// 也可以如下申请,两种申请方式,在内存池中内存的申请顺序不同
let val = Boxed::new_in(&pool, 99).unwrap();
let foo = Boxed::new_in(&pool, Foo { val }).unwrap();
assert_eq!(*foo.val, 99);

有时候需要在栈上分配数据,需要把栈空间适配为Pool接口,则可使用BufPool完成适配

use hipool::{ BufPool, Boxed};
let mut buf = [0_u8; 100];
let mut pool = BufPool::new(&mut buf);
let psize = Boxed::new_in(&pool, 100).unwrap();
assert_eq!(*psize, 100);

有时候分配的Pool也需要在堆上,可以用另外的构造方式,如下:

use hipool::{ MemPool, Boxed };

let mut pool = MemPool::new_boxed(0).unwrap();
let int_array = Boxed::new_slice_then_in(&*pool, 100, |_| {
    Ok(0)
}).unwrap();
int_array.iter().for_each(|n| assert_eq!(*n, 0));

更多的调用接口

use hipool::{ MemPool, Boxed };
use core::alloc::Layout;

let pool = MemPool::new_boxed(0).unwrap();

let val = Boxed::new_in(&*pool, 1).unwrap();
assert_eq!(*val, 1);

let val = Boxed::new_then_in(&*pool, || {
    Ok(100)
}).unwrap();
assert_eq!(*val, 100);

let ivals = [0, 1, 2, 3];
let vals = Boxed::uninit_slice_in::<i32>(&*pool, ivals.len()).unwrap();
let vals = vals.write_slice_then(|n| {Ok(ivals[n])}).unwrap();
assert_eq!(vals[0], 0);
assert_eq!(vals[1], 1);
assert_eq!(vals[2], 2);
assert_eq!(vals[3], 3);

let vals = unsafe { Boxed::new_buf_in(&*pool,
Layout::array::<i32>(2).unwrap()).unwrap().cast_slice::<i32>(2) };
vals.iter().for_each(|val| println!(" {:?} ", val));

let vals = Boxed::new_slice_then_in(&*pool, 2, |n| {
    Ok(n as i32)
}).unwrap();
assert_eq!(vals[0], 0);
assert_eq!(vals[1], 1);

Structs§

Arc
Boxed
BufPool
单线程分配策略,不支持Sync,但是支持Send 因为已分配资源析构的时候并不会访问Pool
Error
错误码有两种使用场景:
MemPool
单线程分配资源,不支持Sync, 但只是Send. 因为已分配资源析构的时候并不会访问Pool 所有内存都在Pool析构的时候集中释放,不存在多线程访问的情况
NullAlloc
PoolAlloc
Rc

Traits§

Allocator
Safety
GenericAlloc
Safety
Pool
Safety

Type Aliases§

BoxedBufPool
BoxedMemPool
Result