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//! Maximum Product Subarray [leetcode: maximum_product_subarray](https://leetcode.com/problems/maximum-product-subarray/) //! //! Given an integer array `nums`, find the contiguous subarray within an array (containing at least one number) which has the largest product. //! //! **Example 1:** //! //! ``` //! Input: [2,3,-2,4] //! Output: 6 //! Explanation: [2,3] has the largest product 6. //! ``` //! //! **Example 2:** //! //! ``` //! Input: [-2,0,-1] //! Output: 0 //! Explanation: The result cannot be 2, because [-2,-1] is not a subarray. //! ``` //! /// # Solutions /// /// # Approach 1: Dynamic Programming /// /// * Time complexity: O(n) /// /// * Space complexity: O(n) /// /// * Runtime: 0 ms /// * Memory: 2.6 MB /// /// ```rust /// use std::cmp; /// /// impl Solution { /// pub fn max_product(nums: Vec<i32>) -> i32 { /// if nums.len() == 0 { return 0; } /// /// let mut dp = vec![vec![0; 2]; 2]; // dp[x][0] max value, dp[x][1] min value /// let mut result = nums[0]; /// /// dp[0][0] = nums[0]; /// dp[0][1] = nums[0]; /// /// for i in 1..nums.len() { /// let (x, y) = (i % 2, (i - 1) % 2); // x, y is 0 or 1 /// /// if nums[i] >= 0 { /// dp[x][0] = cmp::max(dp[y][0] * nums[i], nums[i]); /// dp[x][1] = cmp::min(dp[y][1] * nums[i], nums[i]); /// } else { /// dp[x][0] = cmp::max(dp[y][1] * nums[i], nums[i]); /// dp[x][1] = cmp::min(dp[y][0] * nums[i], nums[i]); /// } /// /// // simplify if else like this /// // dp[x][0] = vec![dp[y][0] * nums[i], dp[y][1] * nums[i], nums[i]].iter().max().unwrap().clone(); /// // dp[x][1] = vec![dp[y][0] * nums[i], dp[y][1] * nums[i], nums[i]].iter().min().unwrap().clone(); /// /// result = cmp::max(dp[x][0], result); /// } /// /// result /// } /// } /// ``` /// /// # Approach 2: Dynamic Programming /// /// * Time complexity: O(n) /// /// * Space complexity: O(1) /// /// * Runtime: 0 ms /// * Memory: 2.5 MB /// /// ```rust /// impl Solution { /// pub fn max_product(nums: Vec<i32>) -> i32 { /// if nums.is_empty() { return 0; } /// /// let mut cur_max = nums[0]; /// let mut cur_min = nums[0]; /// let mut result = nums[0]; /// /// for &num in nums[1..].into_iter() { /// if num >= 0 { /// cur_max = i32::max(cur_max * num, num); /// cur_min = i32::min(cur_min * num, num); /// } else { /// let tmp = cur_max; /// cur_max = i32::max(cur_min * num, num); /// cur_min = i32::min(tmp * num, num); /// } /// /// result = i32::max(cur_max, result); /// } /// /// result /// } /// } /// ``` /// /// # Approach 3: Dynamic Programming /// /// * Time complexity: O(n) /// /// * Space complexity: O(1) /// /// * Runtime: 0 ms /// * Memory: 2.5 MB /// /// ```rust /// use std::mem; /// use std::cmp; /// impl Solution { /// pub fn max_product(nums: Vec<i32>) -> i32 { /// let mut min = nums[0]; /// let mut max = nums[0]; /// let mut res = nums[0]; /// /// for i in 1..nums.len() { /// if nums[i] < 0 { /// mem::swap(&mut min, &mut max); /// } /// /// min = cmp::min(nums[i], min*nums[i]); /// max = cmp::max(nums[i], max*nums[i]); /// /// res = cmp::max(res, max); /// } /// /// return res; /// } /// } /// ``` /// pub fn max_product(nums: Vec<i32>) -> i32 { if nums.is_empty() { return 0; } let mut cur_max = nums[0]; let mut cur_min = nums[0]; let mut result = nums[0]; for &num in nums[1..].into_iter() { if num >= 0 { cur_max = i32::max(cur_max * num, num); cur_min = i32::min(cur_min * num, num); } else { let tmp = cur_max; cur_max = i32::max(cur_min * num, num); cur_min = i32::min(tmp * num, num); } result = i32::max(cur_max, result); } result }