Function dynparser::ast::get_nodename_and_nodes

pub fn get_nodename_and_nodes(node: &Node) -> Result<(&str, &[Node]), Error>

It will get the node name and a slice to the nodes contained by the node

   use dynparser::ast::{self, get_nodename_and_nodes, Node};

   let ast: Node = Node::Rule((
       "root".to_string(),
       vec![Node::Val("hello".to_string())],
   ));

   let (node_name, nodes) = get_nodename_and_nodes(&ast).unwrap();

   assert!(node_name == "root");
   assert!(nodes[0] == ast::Node::Val("hello".to_string()),)