crate_activity/hierarchical_clustering.rs
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crate::ix!();
use std::collections::HashMap;
/// Represents a hierarchical clustering dendrogram node.
#[derive(Debug)]
pub enum Dendrogram {
/// A leaf node representing a single crate.
Leaf {
/// Name of the crate represented by this leaf.
crate_name: String,
},
/// An internal node representing a merge of two clusters.
Internal {
/// Left child cluster.
left: Box<Dendrogram>,
/// Right child cluster.
right: Box<Dendrogram>,
/// The distance at which the two child clusters were merged.
distance: f64,
},
}
/// Errors that can occur during hierarchical clustering.
#[derive(Debug)]
pub enum HierarchicalClusteringError {
/// No crates provided for clustering.
NoCrates,
/// Inconsistent or incomplete data caused shape issues.
DataShapeError,
/// Insufficient correlation data.
IncompleteCorrelationData,
/// Other I/O or data-related issues.
IoError(std::io::Error),
}
/// Perform hierarchical clustering using single-linkage based on crate correlations.
///
/// # Arguments
///
/// * `correlations` - A vector of (crate_a, crate_b, correlation) tuples from `compute_pairwise_correlations`.
///
/// # Returns
///
/// A `Dendrogram` representing the hierarchical clustering structure.
pub fn perform_hierarchical_clustering(
correlations: &[(String, String, f64)]
) -> Result<Dendrogram, HierarchicalClusteringError> {
// Extract unique crate names from the correlation tuples.
let mut crate_set = HashMap::new();
for (a, b, _) in correlations {
crate_set.entry(a.clone()).or_insert(true);
crate_set.entry(b.clone()).or_insert(true);
}
let mut crate_names: Vec<String> = crate_set.keys().cloned().collect();
if crate_names.is_empty() {
// No crates at all means we cannot cluster.
return Err(HierarchicalClusteringError::NoCrates);
}
crate_names.sort(); // Ensure stable ordering of crates.
// Map crate names to indices
let index_map: HashMap<String, usize> = crate_names
.iter()
.enumerate()
.map(|(i, name)| (name.clone(), i))
.collect();
let n = crate_names.len();
// If there's only one crate, hierarchical clustering is trivial.
// Just return a single leaf node.
if n == 1 {
// Single crate scenario: just return a leaf, ignoring correlations.
return Ok(Dendrogram::Leaf {
crate_name: crate_names[0].clone(),
});
}
// Initialize a distance matrix.
// Default distance = 1.0 for missing pairs.
// Distance = 1 - correlation.
let mut distance_matrix = vec![1.0; n * n];
// Distance to self is zero.
for i in 0..n {
distance_matrix[i * n + i] = 0.0;
}
// Fill in distance matrix from correlations
// If not present, distance remains 1.0 (implying no correlation).
for (a, b, corr) in correlations {
if let (Some(&i), Some(&j)) = (index_map.get(a), index_map.get(b)) {
let dist = 1.0 - corr;
let idx1 = i * n + j;
let idx2 = j * n + i;
if idx1 < distance_matrix.len() && idx2 < distance_matrix.len() {
distance_matrix[idx1] = dist;
distance_matrix[idx2] = dist;
} else {
return Err(HierarchicalClusteringError::DataShapeError);
}
}
}
#[derive(Clone)]
struct Cluster {
indices: Vec<usize>,
}
// Each crate starts as its own cluster
let mut clusters: Vec<Cluster> = (0..n).map(|i| Cluster { indices: vec![i] }).collect();
let mut active = vec![true; n]; // which cluster IDs are active
// Each leaf node initially points to a leaf dendrogram
let mut dendrogram_nodes: Vec<Option<Dendrogram>> = crate_names
.iter()
.map(|name| Some(Dendrogram::Leaf { crate_name: name.clone() }))
.collect();
// Perform (n-1) merges
for _step in 0..(n-1) {
// Find the two closest distinct active clusters
let mut min_dist = f64::MAX;
let mut closest_pair = (0, 0);
for i in 0..n {
if !active[i] { continue; }
for j in (i+1)..n {
if !active[j] { continue; }
let dist = cluster_distance(&clusters[i].indices, &clusters[j].indices, &distance_matrix, n)?;
if dist < min_dist {
min_dist = dist;
closest_pair = (i, j);
}
}
}
let (c1, c2) = closest_pair;
let mut new_indices = Vec::new();
new_indices.extend_from_slice(&clusters[c1].indices);
new_indices.extend_from_slice(&clusters[c2].indices);
// Create a new dendrogram node from merging c1 and c2
let left_node = dendrogram_nodes[c1].take().ok_or(HierarchicalClusteringError::DataShapeError)?;
let right_node = dendrogram_nodes[c2].take().ok_or(HierarchicalClusteringError::DataShapeError)?;
let new_node = Dendrogram::Internal {
left: Box::new(left_node),
right: Box::new(right_node),
distance: min_dist,
};
// Merge c2 into c1 and deactivate c2
clusters[c1] = Cluster { indices: new_indices };
dendrogram_nodes[c1] = Some(new_node);
active[c2] = false;
}
// The final active cluster is our root
let final_node = dendrogram_nodes
.into_iter()
.enumerate()
.filter(|(i, _)| active[*i])
.map(|(_, node)| node)
.find(|n| n.is_some())
.ok_or(HierarchicalClusteringError::DataShapeError)?;
final_node.ok_or(HierarchicalClusteringError::DataShapeError)
}
/// Compute single-linkage distance between two clusters.
fn cluster_distance(
c1: &impl AsRef<[usize]>,
c2: &impl AsRef<[usize]>,
distance_matrix: &[f64],
n: usize,
) -> Result<f64, HierarchicalClusteringError> {
let mut min_dist = f64::MAX;
for &i in c1.as_ref() {
for &j in c2.as_ref() {
let idx = i*n + j;
if idx >= distance_matrix.len() {
return Err(HierarchicalClusteringError::DataShapeError);
}
let d = distance_matrix[idx];
if d < min_dist {
min_dist = d;
}
}
}
Ok(min_dist)
}
#[cfg(test)]
mod hierarchical_clustering_tests {
use super::*;
fn correlation_tuple(a: &str, b: &str, corr: f64) -> (String, String, f64) {
(a.to_string(), b.to_string(), corr)
}
#[test]
fn test_no_crates() {
let correlations: Vec<(String, String, f64)> = Vec::new();
let result = perform_hierarchical_clustering(&correlations);
match result {
Err(HierarchicalClusteringError::NoCrates) => (),
_ => panic!("Expected NoCrates error for empty input."),
}
}
#[test]
fn test_single_crate() {
// Single crate means no pairwise correlations.
let correlations: Vec<(String, String, f64)> = Vec::new();
// Since no correlations provided, we cannot infer a second crate.
// So let's consider that no second crate was given at all.
// Actually, if we have only one crate, it must appear in correlations. Let's simulate that:
// If we only have one crate, we can't have correlations. We must handle this scenario
// by providing at least a mention of a crate (but there's no pair). The code
// currently extracts crates from correlation tuples only.
// To handle a single crate scenario properly, we need at least one correlation line referencing it.
// But with one crate, we can't form a pair. For now, let's assume this scenario is not
// possible unless we modify the code to accept crates separately from correlations.
// As a workaround, let's test one crate scenario by forcibly adding a self-pair with correlation=0.
let single_crate_corr = vec![
correlation_tuple("only_crate", "only_crate", 1.0) // This is artificial, but let's assume it.
];
let result = perform_hierarchical_clustering(&single_crate_corr);
if let Ok(dendrogram) = result {
match dendrogram {
Dendrogram::Leaf { crate_name } => {
assert_eq!(crate_name, "only_crate");
},
_ => panic!("Expected a leaf for a single crate."),
}
} else {
panic!("Expected success for single crate scenario.");
}
}
#[test]
fn test_two_crates_no_correlation() {
// Two distinct crates with zero correlation (distance=1.0)
let correlations = vec![correlation_tuple("crateA", "crateB", 0.0)];
let result = perform_hierarchical_clustering(&correlations);
if let Ok(dendrogram) = result {
// Expect a single internal node with two leaves
match dendrogram {
Dendrogram::Internal { left, right, distance } => {
// Distance should be 1 - 0 = 1
assert!((distance - 1.0).abs() < 1e-9);
match (*left, *right) {
(Dendrogram::Leaf { crate_name: ref c1 }, Dendrogram::Leaf { crate_name: ref c2 }) => {
let mut crates = vec![c1.as_str(), c2.as_str()];
crates.sort();
assert_eq!(crates, vec!["crateA", "crateB"]);
},
_ => panic!("Expected two leaf nodes."),
}
},
_ => panic!("Expected an Internal node for two crates."),
}
} else {
panic!("Expected success for two crates no correlation.");
}
}
#[test]
fn test_perfect_correlation() {
// Two identical crates with correlation=1.0
let correlations = vec![correlation_tuple("crateA", "crateB", 1.0)];
let result = perform_hierarchical_clustering(&correlations);
if let Ok(dendrogram) = result {
match dendrogram {
Dendrogram::Internal { distance, .. } => {
// distance = 1 - corr = 0.0 since corr=1.0
assert!((distance - 0.0).abs() < 1e-9);
},
_ => panic!("Expected Internal node for two crates."),
}
} else {
panic!("Expected success for perfect correlation.");
}
}
#[test]
fn test_three_crates_mixed_correlations() {
// crateA and crateB correlate 0.8 -> distance=0.2
// crateB and crateC correlate 0.3 -> distance=0.7
// crateA and crateC no entry => distance=1.0 by default
let correlations = vec![
correlation_tuple("crateA", "crateB", 0.8),
correlation_tuple("crateB", "crateC", 0.3),
];
let result = perform_hierarchical_clustering(&correlations);
if let Ok(dendrogram) = result {
// We expect that the first merge will be between crateA and crateB (closest pair),
// then that cluster merges with crateC.
// The first merge distance: 1 - 0.8 = 0.2 (A-B)
// Then merging (A,B) cluster with C: min distance to C is via crateB (distance=0.7).
match dendrogram {
Dendrogram::Internal { left, right, distance: top_dist } => {
// The top-level merge should be at distance=0.7
assert!((top_dist - 0.7).abs() < 1e-9);
// One side should be crateC leaf, the other side the A-B cluster
let mut leaves = Vec::new();
fn collect_leaves(d: &Dendrogram, leaves: &mut Vec<String>) {
match d {
Dendrogram::Leaf { crate_name } => leaves.push(crate_name.clone()),
Dendrogram::Internal { left, right, .. } => {
collect_leaves(left, leaves);
collect_leaves(right, leaves);
}
}
}
collect_leaves(&*left, &mut leaves);
collect_leaves(&*right, &mut leaves);
leaves.sort();
assert_eq!(leaves, vec!["crateA", "crateB", "crateC"]);
},
_ => panic!("Expected internal node at top."),
}
} else {
panic!("Expected success for three crates mixed correlations.");
}
}
#[test]
fn test_incomplete_correlation_data() {
// Suppose we have three crates, but only one correlation.
// This means some pairs are missing. Our code treats missing as distance=1.0.
// This should still be fine, not produce an error, just larger distances.
let correlations = vec![
correlation_tuple("crateX", "crateY", 0.5),
];
// Should cluster all three crates (X, Y, and maybe a crateZ if we define one)
// Wait, we only have two crates defined above. For three crates test, define three in correlation.
// Actually, to simulate incomplete data:
// Let's say we have crates: crateX, crateY, crateZ
// Provide correlation only for X-Y. Z is never mentioned.
let correlations = vec![
correlation_tuple("crateX", "crateY", 0.5),
];
// Here crateZ is not in correlations at all, so no mention. We must provide it somehow.
// The code currently extracts crates only from correlation tuples. If we don't mention crateZ, it doesn't exist.
// To test incomplete correlation data meaningfully, we need at least mention crateZ with another crate.
// Let's do:
let correlations = vec![
correlation_tuple("crateX", "crateY", 0.5),
correlation_tuple("crateX", "crateZ", 0.0), // X-Z defined, Y-Z missing
];
// Now Y-Z is missing, so Y-Z distance = 1.0, X-Z distance=1.0, X-Y distance=0.5 => dist=0.5
let result = perform_hierarchical_clustering(&correlations);
if let Ok(dendrogram) = result {
// Just ensure it doesn't fail. Check we have three leaves total.
let mut leaves = Vec::new();
fn collect_leaves(d: &Dendrogram, leaves: &mut Vec<String>) {
match d {
Dendrogram::Leaf { crate_name } => leaves.push(crate_name.clone()),
Dendrogram::Internal { left, right, .. } => {
collect_leaves(left, leaves);
collect_leaves(right, leaves);
}
}
}
collect_leaves(&dendrogram, &mut leaves);
leaves.sort();
assert_eq!(leaves, vec!["crateX", "crateY", "crateZ"]);
} else {
panic!("Expected success even with incomplete data (missing pairs).");
}
}
#[test]
fn test_many_crates_low_correlation() {
// Several crates, all with zero correlation => large distances.
// Just test performance & correctness, ensure no panic.
let crates = &["a", "b", "c", "d", "e"];
let mut correlations = Vec::new();
// minimal set of correlations with zero correlation
correlations.push(correlation_tuple("a", "b", 0.0));
correlations.push(correlation_tuple("b", "c", 0.0));
correlations.push(correlation_tuple("c", "d", 0.0));
correlations.push(correlation_tuple("d", "e", 0.0));
// Missing pairs means distance=1.0 anyway.
let result = perform_hierarchical_clustering(&correlations);
if let Ok(dendrogram) = result {
// Collect leaves
let mut leaves = Vec::new();
fn collect_leaves(d: &Dendrogram, leaves: &mut Vec<String>) {
match d {
Dendrogram::Leaf { crate_name } => leaves.push(crate_name.clone()),
Dendrogram::Internal { left, right, .. } => {
collect_leaves(left, leaves);
collect_leaves(right, leaves);
}
}
}
collect_leaves(&dendrogram, &mut leaves);
leaves.sort();
assert_eq!(leaves, vec!["a", "b", "c", "d", "e"]);
} else {
panic!("Expected success with many crates low correlation.");
}
}
// Additional tests could simulate data shape errors by mocking functions or passing
// invalid states, but that requires controlling internal states which may not be trivial.
// The hierarchical clustering code is structured in a way that errors mainly occur on
// empty datasets or indexing issues. We've tested empty (no crates) scenario already.
}