Function async_std::future::timeout[][src]

pub async fn timeout<F, T>(dur: Duration, f: F) -> Result<T, TimeoutError> where
    F: Future<Output = T>, 
Expand description

Awaits a future or times out after a duration of time.

If you want to await an I/O future consider using io::timeout instead.


use std::time::Duration;

use async_std::future;

let never = future::pending::<()>();
let dur = Duration::from_millis(5);
assert!(future::timeout(dur, never).await.is_err());