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use itertools::Itertools;
static ZERO_TO_TEN: [&str; 11] = [
"không", "một", "hai", "ba", "bốn", "năm", "sáu", "bảy", "tám", "chín", "mười",
];
static BASES: [&str; 3] = ["", "ngàn", "triệu"];
static MOT: &str = "mốt";
static LAM: &str = "lăm";
static LE: &str = "lẻ";
static MUOI: &str = "mươi";
static TRAM: &str = "trăm";
static TY: &str = "tỷ";
pub fn say(mut n: u64) -> String {
if n == 0 {
return ZERO_TO_TEN[0].to_string();
}
let mut ret: Vec<&str> = Vec::new();
let mut nbillion = 0;
while n > 0 {
let m = n % 1_000_000_000;
n /= 1_000_000_000;
if m > 0 {
(0..nbillion).for_each(|_| ret.push(TY));
}
say_number_less_than_a_billion(m, &mut ret, n > 0);
nbillion += 1;
}
ret.iter().rev().map(|s| *s).intersperse(" ").collect()
}
#[inline]
fn say_number_less_than_a_billion(mut n: u64, ret: &mut Vec<&str>, more: bool) {
let mut base_index = 0;
while n > 0 {
let hundreds_tens_and_ones = n % 1000;
n /= 1000;
if base_index > 0 && hundreds_tens_and_ones > 0 {
ret.push(BASES[base_index]);
}
let tens_and_ones = hundreds_tens_and_ones % 100;
let hundreds = hundreds_tens_and_ones / 100;
if tens_and_ones == 0 {
} else if tens_and_ones < 10 {
ret.push(ZERO_TO_TEN[tens_and_ones as usize]);
if more || n > 0 || hundreds > 0 {
ret.push(LE);
}
} else {
let ones = tens_and_ones % 10;
let tens = tens_and_ones / 10;
if ones == 1 && tens > 1 {
ret.push(MOT);
} else if ones == 1 {
ret.push(ZERO_TO_TEN[1]);
} else if ones == 5 {
ret.push(LAM);
} else if ones > 0 {
ret.push(ZERO_TO_TEN[ones as usize]);
}
if tens == 1 {
ret.push(ZERO_TO_TEN[10]);
} else {
ret.push(MUOI);
ret.push(ZERO_TO_TEN[tens as usize]);
}
}
if hundreds == 0 {
if (more || n > 0) && tens_and_ones > 0 {
ret.push(TRAM);
ret.push(ZERO_TO_TEN[0]);
}
} else {
ret.push(TRAM);
ret.push(ZERO_TO_TEN[hundreds as usize]);
}
base_index = (base_index + 1) % 3;
}
}