[][src]Struct peekmore::PeekMoreIterator

pub struct PeekMoreIterator<I: Iterator> { /* fields omitted */ }

This iterator makes it possible to peek multiple times without consuming a value. In reality the underlying iterator will be consumed, but the values will be stored in a queue. This queue allows us to peek at unconsumed elements (as far as the multi-peek iterator is concerned). When the iterator consumes an element, the element at the front of the queue will be dequeued, and will no longer be peekable.

Implementations

impl<I: Iterator> PeekMoreIterator<I>[src]

pub fn peek(&mut self) -> Option<&I::Item>[src]

Get a reference to the element where the cursor currently points to. If no such element exists, return None will be returned.

If we haven't advanced our cursor, it will point to the same element as Iterator::next() would return. Note that the cursor can't point to an element before the first unconsumed element within the iterator. In a sense the cursor moves independently within the iterator. But it can only point to unconsumed elements.

The following illustration aims to show how peek() behaves. i represents the position of the iterator (i.e. the next value that will be returned if next() is called) and j represents the position of the cursor (i.e. the current element referenced if peek() is called). In example code next to the illustrations, the first element 1 is analogous to A, 2 to B, etc.

The example below primarily uses advance_cursor() to move the cursor and peek() to peek at the element the cursor points to, but many often more convenient methods exist to change the element cursor points at, or to peek at those elements.

  • Let's start:
use peekmore::PeekMore;

// Initialize our iterator.
let iterable = [1, 2, 3, 4];
let mut iterator = iterable.iter().peekmore();
-----     -----      -----     -----
| A | --> | B |  --> | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
  ^
  i, j
  • Call peek():
let j = iterator.peek();
assert_eq!(j, Some(&&1));
-----     -----      -----     -----
| A | --> | B |  --> | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
  ^
  i, j
     returns Some(&A)

  • Call advance_cursor()
let iter = iterator.advance_cursor();
-----     -----      -----     -----
| A | --> | B |  --> | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
  ^         ^
  i         j
  • Call peek()

The reference returned by peek() will not change, similar to the behaviour of core::iter::Peekable::peek. In order to move to the next peekable element, we need to advance the cursor.

let j = iterator.peek();
assert_eq!(j, Some(&&2));

// Calling `peek()` multiple times doesn't shift the position of the cursor;
// a reference to the same element will be returned each call.
assert_eq!(iterator.peek(), Some(&&2));
assert_eq!(iterator.peek(), Some(&&2));
-----     -----      -----     -----
| A | --> | B |  --> | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
  ^         ^
  i         j
            returns Some(&B)
  • Call next()

By calling next, the underlying iterator will be advanced andthe element represented by A will be consumed. It won't be possible to peek at A anymore.

let i = iterator.next();
assert_eq!(i, Some(&1));
-----     -----      -----     -----
| A |     | B |  --> | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
            ^
            i, j
 returns Some(A)
  • Call next().

The underlying iterator is advanced again. As a result, the cursor position also shifts to the next iterator position, which happens if the underlying iterator consumed an element where our cursor pointed at (that is if j < i).

// Show that the cursor still points at the second element.
let j = iterator.peek();
assert_eq!(j, Some(&&2));

// Consume the second element.
let i = iterator.next();
assert_eq!(i, Some(&2));

// Our cursor previously pointed at the element represented by B. Since that element has
// been consumed, the cursor shifts to the next unconsumed element: C.
let j = iterator.peek();
assert_eq!(j, Some(&&3));

-----     -----      -----     -----
| A |     | B |      | C | --> | D | --> None --> None --> ...
-----     -----      -----     -----
                       ^
                       i, j
          returns Some(B)
  • Consume more elements by calling next() until we reach None:
let i = iterator.next();
assert_eq!(i, Some(&3));

let j = iterator.peek();
assert_eq!(j, Some(&&4));

let i = iterator.next();
assert_eq!(i, Some(&4));

let j = iterator.peek();
assert_eq!(j, None);

let i = iterator.next();
assert_eq!(i, None);

pub fn peek_next(&mut self) -> Option<&I::Item>[src]

Advance the cursor to the next element and return a reference to that value.

pub fn peek_previous(&mut self) -> Result<Option<&I::Item>, PeekMoreError>[src]

Try to peek at a previous element. If no such element exists, an Err result containing a PeekMoreError::ElementHasBeenConsumed will be returned.

If a previous element does exist, an option wrapped in an Ok result will be returned.

pub fn peek_forward(&mut self, n: usize) -> Option<&I::Item>[src]

Move the cursor n steps forward and peek at the element the cursor then points to.

pub fn peek_backward(
    &mut self,
    n: usize
) -> Result<Option<&I::Item>, PeekMoreError>
[src]

Move the cursor n steps backward and peek at the element the cursor then points to.

If there aren't n elements prior to the element the cursor currently points at, a PeekMoreError::ElementHasBeenConsumed is returned instead. The cursor will then stay at the position it was prior to calling this method.

If you want to peek at the first unconsumed element instead of returning with an error, you can use the peek_backward_or_first method instead.

pub fn peek_backward_or_first(&mut self, n: usize) -> Option<&I::Item>[src]

Move the cursor n steps backward and peek at the element the cursor then points to, or if there aren't n elements prior to the element the cursor currently points to, peek at the first unconsumed element instead.

pub fn peek_nth(&mut self, n: usize) -> Option<&I::Item>[src]

Peek at the nth element without moving the cursor.

pub fn advance_cursor(&mut self) -> &mut PeekMoreIterator<I>

Notable traits for PeekMoreIterator<I>

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I> type Item = I::Item;
[src]

Advance the cursor to the next peekable element.

This method does not advance the iterator itself. To advance the iterator, call next() instead.

A mutable reference to the iterator is returned, which allows the operation to be chained.

pub fn advance_cursor_by(&mut self, n: usize) -> &mut PeekMoreIterator<I>

Notable traits for PeekMoreIterator<I>

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I> type Item = I::Item;
[src]

Advance the cursor n elements forward.

This does not advance the iterator itself. To advance the iterator, call next() instead.

pub fn advance_cursor_while<P: Fn(Option<&I::Item>) -> bool>(
    &mut self,
    predicate: P
) -> &mut PeekMoreIterator<I>

Notable traits for PeekMoreIterator<I>

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I> type Item = I::Item;
[src]

Moves the cursor forward until the predicate is no longer true.

pub fn move_cursor_back(
    &mut self
) -> Result<&mut PeekMoreIterator<I>, PeekMoreError>
[src]

Move the cursor to the previous peekable element. If such an element doesn't exist, a PeekMoreError::ElementHasBeenConsumed will be returned.

If we can move to a previous element, a mutable reference to the iterator, wrapped in the Ok variant of Result will be returned.

pub fn move_cursor_back_by(
    &mut self,
    n: usize
) -> Result<&mut PeekMoreIterator<I>, PeekMoreError>
[src]

Move the cursor n elements backward. If there aren't n unconsumed elements prior to the cursor, an error will be returned instead. In case of an error, the cursor will stay at the position it pointed at prior to calling this method.

If you want to reset the cursor to the first unconsumed element even if there aren't n unconsumed elements before the cursor position, the move_backward_or_reset method can be used.

pub fn move_cursor_back_or_reset(
    &mut self,
    n: usize
) -> &mut PeekMoreIterator<I>

Notable traits for PeekMoreIterator<I>

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I> type Item = I::Item;
[src]

Move the cursor n elements backward, or reset its position to the first non-consumed element. The latter happens when the cursor position is smaller than the elements it has to move backwards by.

pub fn move_nth(&mut self, n: usize) -> &mut PeekMoreIterator<I>

Notable traits for PeekMoreIterator<I>

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I> type Item = I::Item;
[src]

Move the cursor to the n-th element of the queue.

pub fn reset_view(&mut self)[src]

👎 Deprecated

Deprecated: use reset_cursor instead.

pub fn reset_cursor(&mut self)[src]

Reset the position of the cursor.

If peek is called just after a reset, it will return a reference to the first element.

pub fn truncate_iterator_to_cursor(&mut self)[src]

Remove all elements from the start of the iterator until reaching the same position as the cursor by calling Iterator::next().

After calling this method, iter.peek() == iter.next().as_ref().

 use peekmore::PeekMore;

 let iterable = [1, 2, 3, 4];
 let mut iter = iterable.iter().peekmore();

 iter.advance_cursor_by(2);
 assert_eq!(iter.peek(), Some(&&3));
 assert_eq!(iter.next(), Some(&1));
 iter.truncate_iterator_to_cursor();
 assert_eq!(iter.peek(), Some(&&3));
 assert_eq!(iter.next(), Some(&3));

pub fn peek_range(&mut self, start: usize, end: usize) -> &[Option<I::Item>][src]

Returns a view into the next start (inclusive) to end (exclusive) elements.

Note: start and end represent indices and start at 0. These indices always start at the beginning of the queue (the unconsumed iterator) and don't take the position of the cursor into account.

Panics

Panics if start > end, in which case the range would be negative.

use peekmore::PeekMore;

let iterable = [1, 2, 3, 4];
let mut iter = iterable.iter().peekmore();

match iter.peek_range(1, 3) {
    [Some(2), Some(p)] => println!("Yay! we found number {} after number 2", p),
    _ => println!("Oh noes!"),
}

pub fn peek_amount(&mut self, n: usize) -> &[Option<I::Item>][src]

Returns a view into the next n unconsumed elements of the iterator.

Here, n represents the amount of elements as counted from the start of the unconsumed iterator.

For example, if we created a (peekmore) iterator from the array [1, 2, 3] and consume the first element by calling the regular Iterator::next method, and then call peek_amount(3), the iterator will return &[Some(2), Some(3), None]. Here Some(2) and Some(3) are queued elements which we can peek at, and are not consumed by the iterator yet. None is the last element returned by our view, since our original iterator is sized and doesn't contain more elements. Thus in the absence of additional elements, we return None. This method is a variation on peek_range. You could instead have called peek_range(0, n) (note that peek_range takes indices as arguments instead of an amount).

Note: This method does not use or modify the position of the cursor.

Example:

use peekmore::PeekMore;

let iterable = [1, 2, 3];
let mut iter = iterable.iter().peekmore();

match iter.peek_amount(4) { // -> &[Option(&1), Option(&2), Option(&3), None]
  [Some(a), Some(b), Some(c), None] => println!("Found a match ({}, {}, {}) ", a, b, c),
  _ => eprintln!("Expected (just) 3 more values"),
}

Trait Implementations

impl<I: Clone + Iterator> Clone for PeekMoreIterator<I> where
    I::Item: Clone
[src]

impl<I: Debug + Iterator> Debug for PeekMoreIterator<I> where
    I::Item: Debug
[src]

impl<I: ExactSizeIterator> ExactSizeIterator for PeekMoreIterator<I>[src]

Uses ExactSizeIterator default implementation.

impl<I: FusedIterator> FusedIterator for PeekMoreIterator<I>[src]

Uses FusedIterator default implementation.

impl<'a, I: Iterator> Iterator for PeekMoreIterator<I>[src]

type Item = I::Item

The type of the elements being iterated over.

Auto Trait Implementations

impl<I> Send for PeekMoreIterator<I> where
    I: Send,
    <I as Iterator>::Item: Send
[src]

impl<I> Sync for PeekMoreIterator<I> where
    I: Sync,
    <I as Iterator>::Item: Sync
[src]

impl<I> Unpin for PeekMoreIterator<I> where
    I: Unpin,
    <I as Iterator>::Item: Unpin
[src]

Blanket Implementations

impl<T> Any for T where
    T: 'static + ?Sized
[src]

impl<T> Borrow<T> for T where
    T: ?Sized
[src]

impl<T> BorrowMut<T> for T where
    T: ?Sized
[src]

impl<T> From<T> for T[src]

impl<T, U> Into<U> for T where
    U: From<T>, 
[src]

impl<I> IntoIterator for I where
    I: Iterator
[src]

type Item = <I as Iterator>::Item

The type of the elements being iterated over.

type IntoIter = I

Which kind of iterator are we turning this into?

impl<I> PeekMore for I where
    I: Iterator
[src]

impl<T> ToOwned for T where
    T: Clone
[src]

type Owned = T

The resulting type after obtaining ownership.

impl<T, U> TryFrom<U> for T where
    U: Into<T>, 
[src]

type Error = Infallible

The type returned in the event of a conversion error.

impl<T, U> TryInto<U> for T where
    U: TryFrom<T>, 
[src]

type Error = <U as TryFrom<T>>::Error

The type returned in the event of a conversion error.