[−][src]Function secp256kfun::op::scalar_sub
pub fn scalar_sub<Z1, Z2, S1, S2>(
x: &Scalar<S1, Z1>,
y: &Scalar<S2, Z2>
) -> Scalar<Secret, Zero>
Subtracts one scalar from another
pub fn scalar_sub<Z1, Z2, S1, S2>(
x: &Scalar<S1, Z1>,
y: &Scalar<S2, Z2>
) -> Scalar<Secret, Zero>
Subtracts one scalar from another