Function mpstthree::functionmpst::choose::choose_left_mpst_session_b_to_all[][src]

pub fn choose_left_mpst_session_b_to_all<'a, S0, S1, S2, S3, S4, S5, R0, R1, R2, R3, R4, R5>(
    s: MeshedChannels<ChooseMpst<S2, S0, S4, S1, R0, R1, RoleADual<RoleEnd>>, ChooseMpst<<S0 as Session>::Dual, <<S3 as Session>::Dual as Session>::Dual, <S1 as Session>::Dual, <<S5 as Session>::Dual as Session>::Dual, R2, R3, RoleCDual<RoleEnd>>, RoleBtoAll<R4, R5>, RoleB<RoleEnd>>
) -> MeshedChannels<S2, S3, R4, RoleB<RoleEnd>> where
    S0: Session + 'a,
    S1: Session + 'a,
    S2: Session + 'a,
    S3: Session + 'a,
    S4: Session + 'a,
    S5: Session + 'a,
    R0: Role + 'a,
    R1: Role + 'a,
    R2: Role + 'a,
    R3: Role + 'a,
    R4: Role + 'a,
    R5: Role + 'a, 
Expand description

Given a choice from B, to other processes, between two MeshedChannels, choose the first option for each.

B has to encapsulate all possible MeshedChannels for each other role. This function creates the 6 new binary Session, the 3 new Role related to each first option then the related [mpstthree::meshedchannels:: MeshedChannels]. It then sends those options to the related processes.

  • S0: dual session from A to C on left branch

  • S1: dual session from A to C on right branch

  • S2: session from B to A on left branch

  • S3: session from B to C on left branch

  • S4: session from B to A on right branch

  • S5: session from B to C on right branch

  • R0: dual stack of A on left branch

  • R1: dual stack of A on right branch

  • R2: dual stack of C on left branch

  • R3: dual stack of C on right branch

  • R4: stack of B on left branch

  • R5: stack of B on right branch