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/* * Copyright (c) 2020 Erik Nordstrøm <erik@nordstroem.no> * * Permission to use, copy, modify, and/or distribute this software for any * purpose with or without fee is hereby granted, provided that the above * copyright notice and this permission notice appear in all copies. * * THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES * WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF * MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR * ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN * ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF * OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE. */ solution_printer!(8, print_solution, input_generator, INPUT, solve_part_1, solve_part_2); pub const INPUT: &str = include_str!("../input/2019/day8.txt"); /// ### Day 8: Space Image Format /// /// [https://adventofcode.com/2019/day/8](https://adventofcode.com/2019/day/8) /// /// The Elves' spirits are lifted when they realize you have an opportunity to /// reboot one of their Mars rovers, and so they are curious if you would spend /// a brief sojourn on Mars. You land your ship near the rover. /// /// When you reach the rover, you discover that it's already in the process of /// rebooting! It's just waiting for someone to enter a [BIOS](https://en.wikipedia.org/wiki/BIOS) password. The Elf /// responsible for the rover takes a picture of the password (your puzzle /// input) and sends it to you via the Digital Sending Network. /// /// Unfortunately, images sent via the Digital Sending Network aren't encoded /// with any normal encoding; instead, they're encoded in a special Space Image /// Format. None of the Elves seem to remember why this is the case. They send /// you the instructions to decode it. /// /// Images are sent as a series of digits that each represent the color of a /// single pixel. The digits fill each row of the image left-to-right, then /// move downward to the next row, filling rows top-to-bottom until every pixel /// of the image is filled. /// /// Each image actually consists of a series of identically-sized *layers* that /// are filled in this way. So, the first digit corresponds to the top-left /// pixel of the first layer, the second digit corresponds to the pixel to the /// right of that on the same layer, and so on until the last digit, which /// corresponds to the bottom-right pixel of the last layer. /// /// For example, given an image `3` pixels wide and `2` pixels tall, the image data /// `123456789012` corresponds to the following image layers: /// /// ```text /// Layer 1: 123 /// 456 /// /// Layer 2: 789 /// 012 /// ``` /// /// The image you received is *`25` pixels wide and `6` pixels tall*. /// /// To make sure the image wasn't corrupted during transmission, the Elves /// would like you to find the layer that contains the *fewest `0` digits*. On that /// layer, what is *the number of `1` digits multiplied by the number of `2` digits?* /// /// ### Solution /// /// ⚠️ SPOILER ALERT ⚠️ /// /// ``` /// use codetrotter_aoc_2019_solutions::day_08::{INPUT, input_generator, solve_part_1}; /// assert_eq!(solve_part_1(&input_generator(INPUT)), 2032); /// ``` pub fn solve_part_1 (input_image_data: &ImageData) -> usize { let mut lowest_amount_of_zeros = usize::max_value(); let mut answer = 0; for layer in input_image_data { let mut disregard_layer = false; let (mut num_zeros_in_layer, mut num_ones_il, mut num_twos_il) = (0,0,0); for &pixel_value in layer.iter() { if pixel_value == 0 { num_zeros_in_layer += 1; if num_zeros_in_layer >= lowest_amount_of_zeros { disregard_layer = true; break; } } else if pixel_value == 1 { num_ones_il += 1; } else if pixel_value == 2 { num_twos_il += 1; } } if !disregard_layer { lowest_amount_of_zeros = num_zeros_in_layer; answer = num_ones_il * num_twos_il; } } answer } pub const IMAGE_WIDTH: usize = 25; pub const IMAGE_HEIGHT: usize = 6; pub const PIXELS_PER_LAYER: usize = IMAGE_WIDTH * IMAGE_HEIGHT; pub type ImageData = Vec<LayerData>; pub type LayerData = [u8; PIXELS_PER_LAYER]; pub fn input_generator (image_str: &str) -> ImageData { let mut image_str = image_str.trim_end(); let mut image_data = ImageData::new(); loop { let chunk = &image_str[..PIXELS_PER_LAYER]; image_str = &image_str[PIXELS_PER_LAYER..]; let mut layer_pixels = [0; PIXELS_PER_LAYER]; let hurr: Vec<_> = chunk.chars().map(|c| c.to_digit(10).unwrap() as u8).collect(); layer_pixels.copy_from_slice(&hurr); image_data.push(layer_pixels); if image_str.len() == 0 { break; } } image_data } /// ### Day 8, Part Two /// /// [https://adventofcode.com/2019/day/8#part2](https://adventofcode.com/2019/day/8#part2) /// /// Now you're ready to decode the image. The image is rendered by stacking the /// layers and aligning the pixels with the same positions in each layer. The /// digits indicate the color of the corresponding pixel: `0` is black, `1` is /// white, and `2` is transparent. /// /// The layers are rendered with the first layer in front and the last layer in /// back. So, if a given position has a transparent pixel in the first and /// second layers, a black pixel in the third layer, and a white pixel in the /// fourth layer, the final image would have a *black* pixel at that position. /// /// For example, given an image `2` pixels wide and `2` pixels tall, the image data /// `0222112222120000` corresponds to the following image layers: /// /// ```text /// Layer 1: 02 /// 22 /// /// Layer 2: 11 /// 22 /// /// Layer 3: 22 /// 12 /// /// Layer 4: 00 /// 00 /// ``` /// /// Then, the full image can be found by determining the top visible pixel in /// each position: /// /// - The top-left pixel is *black* because the top layer is `0`. /// - The top-right pixel is *white* because the top layer is `2` (transparent), /// but the second layer is `1`. /// - The bottom-left pixel is *white* because the top two layers are `2`, but /// the third layer is `1`. /// - The bottom-right pixel is *black* because the only visible pixel in that /// position is `0` (from layer 4). /// /// So, the final image looks like this: /// /// ```text /// 01 /// 10 /// ``` /// /// *What message is produced after decoding your image?* /// /// ### Solution /// /// ⚠️ SPOILER ALERT ⚠️ /// /// ``` /// use codetrotter_aoc_2019_solutions::day_08::{INPUT, input_generator, solve_part_2, FlattenedImage, PIXELS_PER_LAYER}; /// let flattened = FlattenedImage /// { /// flattened: /// [ /// 0,1,1,0,0,1,1,1,1,0,0,1,1,0,0,1,0,0,1,0,0,1,1,0,0, // " XXXX XXXXXXXX XXXX XX XX XXXX " /// 1,0,0,1,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0, // "XX XX XX XX XX XX XX XX XX " /// 1,0,0,0,0,1,1,1,0,0,1,0,0,0,0,1,0,0,1,0,1,0,0,0,0, // "XX XXXXXX XX XX XX XX " /// 1,0,0,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,1,0,1,1,0, // "XX XX XX XX XX XX XXXX " /// 1,0,0,1,0,1,0,0,0,0,1,0,0,1,0,1,0,0,1,0,1,0,0,1,0, // "XX XX XX XX XX XX XX XX XX " /// 0,1,1,0,0,1,0,0,0,0,0,1,1,0,0,0,1,1,0,0,0,1,1,1,0, // " XXXX XX XXXX XXXX XXXXXX " /// ], /// }; /// // XXX: Originally I was planning on decoding the image into a string, /// // but unless the whole font is embedded in our input and using /// // some kind of masking that we could figure out without too much /// // trouble and get the glyphs for all of the possible characters, /// // we are not able to decode the pictured string for all of the /// // different inputs that the AoC servers is able to give. /// // So, unfortunately we are left for now with just outputting /// // the flattened image and leaving the reading of the value shown /// // in the image to humans running the program. /// assert_eq!(solve_part_2(&input_generator(INPUT)), flattened); /// ``` pub fn solve_part_2 (input_image_data: &ImageData) -> FlattenedImage { input_image_data.flatten() } pub struct FlattenedImage { pub flattened: LayerData, } impl FlattenedImage { fn new () -> Self { Self { flattened: [2; PIXELS_PER_LAYER], } } } impl std::fmt::Display for FlattenedImage { fn fmt (&self, f: &mut std::fmt::Formatter<'_>) -> std::fmt::Result { for y in 0..IMAGE_HEIGHT { for x in 0..IMAGE_WIDTH { match self.flattened[y * IMAGE_WIDTH + x] { 0 => write!(f, " ")?, 1 => write!(f, "XX")?, 2 => write!(f, " ")?, _ => unreachable!(), } } writeln!(f)?; } Ok(()) } } impl std::fmt::Debug for FlattenedImage { fn fmt (&self, f: &mut std::fmt::Formatter<'_>) -> std::fmt::Result { for y in 0..IMAGE_HEIGHT { for x in 0..IMAGE_WIDTH { write!(f, "{},", self.flattened[y * IMAGE_WIDTH + x])?; } writeln!(f)?; } Ok(()) } } impl PartialEq for FlattenedImage { fn eq (&self, other: &Self) -> bool { for (i, &pixel) in self.flattened.iter().enumerate() { if pixel != other.flattened[i] { return false; } } true } } trait Flatten { fn flatten (&self) -> FlattenedImage; } impl Flatten for ImageData { fn flatten (&self) -> FlattenedImage { let mut flattened = FlattenedImage::new(); let mut pixels_remaining: Vec<_> = (0..PIXELS_PER_LAYER).collect(); for layer in self { pixels_remaining.retain(|&i| { if layer[i] != 2 { flattened.flattened[i] = layer[i]; return false; } true }); if pixels_remaining.len() == 0 { break; } } flattened } }