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use std::collections::HashSet;
pub fn part1(input: &[i32]) -> i32 {
input.iter().sum()
}
pub fn part2(input: &[i32]) -> i32 {
let mut current: i32 = 0;
let mut seen = HashSet::new();
seen.insert(current);
for x in input.iter().cycle() {
current += x;
if !seen.insert(current) {
return current;
}
}
unreachable!()
}
#[test]
fn examples() {
assert_eq!(part1(&[1, 1, 1]), 3);
assert_eq!(part1(&[1, 1, -2]), 0);
assert_eq!(part1(&[-1, -2, -3]), -6);
assert_eq!(part2(&[1, -1]), 0);
assert_eq!(part2(&[3, 3, 4, -2, -4]), 10);
assert_eq!(part2(&[-6, 3, 8, 5, -6]), 5);
assert_eq!(part2(&[7, 7, -2, -7, -4]), 14);
}
#[test]
fn solution() {
use std::str::FromStr;
let input = include_str!("input/1");
let numbers: Vec<i32> = input
.lines()
.filter_map(|s| i32::from_str(s).ok())
.collect();
assert_eq!(part1(&numbers), 525);
assert_eq!(part2(&numbers), 75749);
}