Function aabb3::intersects

pub fn intersects<'a, 'b, T>(a: &'a AABB3<T>, b: &'b AABB3<T>) -> bool where
    T: Copy + Num, 

Examples

use aabb3::{self, AABB3};
let mut a = aabb3::new([1, 1, 1], [2, 2, 2]);
let mut b = aabb3::new([-2, -2, -2], [-1, -1, -1]);
let mut c = aabb3::new([-1, -1, -1], [1, 1, 1]);
assert!(!aabb3::intersects(&a, &b));
assert!(aabb3::intersects(&a, &c));
assert!(aabb3::intersects(&b, &c));